Bash 脚本：循环执行后始终显示菜单
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/20224862/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Bash script: always show menu after loop execution
提问by EightBall
I'm using a bash script menu like this:
我正在使用这样的 bash 脚本菜单：
#!/bin/bash
PS3='Please enter your choice: '
options=("Option 1" "Option 2" "Option3" "Quit")
select opt in "${options[@]}"
do
case $opt in
"Option 1")
echo "you chose choice 1"
;;
"Option 2")
echo "you chose choice 2"
;;
"Option 3")
echo "you chose choice 3"
;;
"Quit")
break
;;
*) echo invalid option;;
esac
done
After each menu selection I just get prompted with
每次选择菜单后，我都会收到提示
Please enter your choice:
How do I always show the menu after each option has finished execution? I've done some looking around and I think I can do some kind of while loop, but I haven't been able to get anything working.
如何在每个选项完成执行后始终显示菜单？我环顾四周，我想我可以做某种 while 循环，但是我什么都没做。
回答by thom
Make it beautiful and userfriendly ;-)
使它美观和用户友好;-)
#!/bin/bash
while :
do
clear
cat<<EOF
==============================
Menusystem experiment
------------------------------
Please enter your choice:
Option (1)
Option (2)
Option (3)
(Q)uit
------------------------------
EOF
read -n1 -s
case "$REPLY" in
"1") echo "you chose choice 1" ;;
"2") echo "you chose choice 2" ;;
"3") echo "you chose choice 3" ;;
"Q") exit ;;
"q") echo "case sensitive!!" ;;
* ) echo "invalid option" ;;
esac
sleep 1
done
Replace the echos in this example with function calls or calls to other scripts.
用函数调用或对其他脚本的调用替换本例中的回声。
回答by Ranjithkumar T
just modified your script like below. its working for me !
刚刚修改了你的脚本，如下所示。它对我来说有效！
#!/bin/bash
while true
do
PS3='Please enter your choice: '
options=("Option 1" "Option 2" "Option 3" "Quit")
select opt in "${options[@]}"
do
case $opt in
"Option 1")
echo "you chose choice 1"
break
;;
"Option 2")
echo "you chose choice 2"
break
;;
"Option 3")
echo "you chose choice 3"
break
;;
"Quit")
echo "Thank You..."
exit
;;
*) echo invalid option;;
esac
done
done
回答by Jay
You can also do something like:
您还可以执行以下操作：
#!/bin/bash
PS3='Please enter your choice: '
options=("Option 1" "Option 2" "Option 3" "Quit")
select opt in "${options[@]}"
do
case $opt in
"Option 1")
echo "you chose choice 1"
;;
"Option 2")
echo "you chose choice 2"
;;
"Option 3")
echo "you chose choice 3"
;;
"Quit")
break
;;
*) echo invalid option;;
esac
counter=1
SAVEIFS=$IFS
IFS=$(echo -en "\n\b") # we set another delimiter, see also: https://www.cyberciti.biz/tips/handling-filenames-with-spaces-in-bash.html
for i in ${options[@]};
do
echo $counter')' $i
let 'counter+=1'
done
IFS=$SAVEIFS
done
