Java 获取错误:尝试运行 Apache-Tomcat 的 startup.bat 时未正确定义 JRE_HOME 变量

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时间:2020-08-11 07:09:11  来源:igfitidea点击:

Getting Error:JRE_HOME variable is not defined correctly when trying to run startup.bat of Apache-Tomcat

javaapachetomcatbatch-file

提问by Rajeev Dixit

When trying to start Tomcat Server through cmd prompt using 'startup.bat' getting error as-"JRE_HOME variable is not defined correctly. The environment variable is needed to Run this program" Defined Environment path as-

当尝试使用 'startup.bat' 通过 cmd 提示符启动 Tomcat 服务器时,出现错误为-“JRE_HOME 变量未正确定义。运行此程序需要环境变量”定义的环境路径为-

CATALINA_HOME-C:\Program Files\Java\apache-tomcat-7.0.59\apache-tomcat-7.0.59
JAVA_HOME-C:\Program Files\Java\jdk1.8.0_25;
JRE_Home-C:\Program Files\Java\jre1.8.0_25\bin;

CATALINA_HOME-C:\Program Files\Java\apache-tomcat-7.0.59\apache-tomcat-7.0.59
JAVA_HOME-C:\Program Files\Java\jdk1.8.0_25;
JRE_Home-C:\Program Files\Java\jre1.8.0_25\bin;

采纳答案by Rajeev Dixit

Got the solution and it's working fine. Set the environment variables as:

得到了解决方案,它工作正常。将环境变量设置为:

  • CATALINA_HOME=C:\Program Files\Java\apache-tomcat-7.0.59\apache-tomcat-7.0.59(path where your Apache Tomcat is)
  • JAVA_HOME=C:\Program Files\Java\jdk1.8.0_25;(path where your JDK is)
  • JRE_Home=C:\Program Files\Java\jre1.8.0_25;(path where your JRE is)
  • CLASSPATH=%JAVA_HOME%\bin;%JRE_HOME%\bin;%CATALINA_HOME%\lib
  • CATALINA_HOME=C:\Program Files\Java\apache-tomcat-7.0.59\apache-tomcat-7.0.59(您的 Apache Tomcat 所在的路径)
  • JAVA_HOME=C:\Program Files\Java\jdk1.8.0_25;(你的JDK所在的路径)
  • JRE_Home=C:\Program Files\Java\jre1.8.0_25;(您的 JRE 所在的路径)
  • CLASSPATH=%JAVA_HOME%\bin;%JRE_HOME%\bin;%CATALINA_HOME%\lib

回答by Hypino

Your JRE_HOME does not need to point to the "bin" directory. Just set it to C:\Program Files\Java\jre1.8.0_25

您的 JRE_HOME 不需要指向“bin”目录。只需将其设置为C:\Program Files\Java\jre1.8.0_25