Python 从列表中删除所有空元素
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Removing all empty elements from a list
提问by Clone
Why does my code not remove the last empty element in the list?
为什么我的代码没有删除列表中的最后一个空元素？
templist = ['', 'hello', '', 'hi', 'mkay', '', '']
for element in templist:
if element == '':
templist.remove(element)
print (templist)
Output:
输出：
['hello', 'hi', 'mkay', '']
回答by Elliot Roberts
Well, you could always just do this:
好吧，你总是可以这样做：
new_list = list(filter(None, templist))
回答by mhawke
Because you are mutating the list that is being iterating over. Think of it as if the for loop is iterating using an index; removing elements reduces the length of the list thereby invalidating indices > len(list) - 1.
因为您正在改变正在迭代的列表。把它想象成 for 循环正在使用索引进行迭代；删除元素会减少列表的长度，从而使索引 > 无效len(list) - 1。
The "Pythonic" solution to this is to use a list comprehension:
对此的“Pythonic”解决方案是使用列表理解：
templist = ['', 'hello', '', 'hi', 'mkay', '', '']
templist[:] = [item for item in templist if item != '']
This performs in placeremoval of items from the list.
这会从列表中就地删除项目。
回答by Dimitris Fasarakis Hilliard
To point out your error, by iterating through a copy of the list, i.e changing your forstatement to:
要指出您的错误，请遍历列表的副本，for即将您的语句更改为：
for element in templist[:]:
Altering a list while you iterate over it leads to the odd results you see.
在迭代列表时更改列表会导致您看到的奇怪结果。
More compactly, you could use filterfor this:
更简洁地，您可以使用filter：
templist = list(filter(None, templist))
when Noneis supplied to it, it simply returns elements that are true (empty strings evaluate to false).
当None提供给它时，它只返回为真的元素（空字符串计算为假）。
回答by computeriscomputer
You could make a new list called wordGrabberfor example and instead of removing the blanks you could populate your new list with content
您可以创建一个名为wordGrabber例如的新列表，而不是删除空白，您可以使用内容填充新列表
templist = ['', 'hello', '', 'hi', 'mkay', '', '']
for element in templist:
if element != '':
wordGrabber.append(element)
print (wordGrabber)
