Python numpy.sin 函数的度数？
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numpy.sin function in degrees?
提问by Daniil Ukhorskiy
I'm working on a problem that has to do with calculating angles of refraction and what not. However, it seems that I'm unable to use the numpy.sin() function in degrees. I have tried to use numpy.degrees() and numpy.rad2deg().
我正在研究一个与计算折射角有关的问题。但是，似乎我无法以度为单位使用 numpy.sin() 函数。我曾尝试使用 numpy.degrees() 和 numpy.rad2deg()。
numpy.sin(90)
numpy.degrees(numpy.sin(90))
Both return ~ 0.894 and ~ 51.2 respectively.
两者分别返回 ~ 0.894 和 ~ 51.2。
Thanks for your help.
谢谢你的帮助。
采纳答案by BrenBarn
You don't want to convert todegrees, because you already have your number (90) in degrees. You need to convert 90 fromdegrees to radians, and you need to do it beforeyou take the sine:
您不想转换为度数，因为您已经有了以度为单位的数字 (90)。您需要将 90从度数转换为弧度，并且需要在取正弦之前进行：
>>> np.sin(np.deg2rad(90))
1.0
(You can use either deg2rador radians.)
（您可以使用deg2rad或radians。）
回答by Malik Brahimi
Use the mathmodule from the standard Python library:
使用math标准 Python 库中的模块：
>>> math.sin(math.radians(90))
