是否可以在 bash 脚本中检测 32 位和 64 位？
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Is it possible to detect 32 bit vs 64 bit in a bash script?
提问by Mike Stone
I am writing a bash script to deal with some installations in an automated way... I have the possibility of getting one such program in 32 or 64 bit binary... is it possible to detect the machine architecture from bash so I can select the correct binary?
我正在编写一个 bash 脚本来以自动方式处理一些安装......我有可能在 32 位或 64 位二进制文件中获得一个这样的程序......是否可以从 bash 检测机器架构，以便我可以选择正确的二进制？
This will be for Ubuntu machines.
这将适用于 Ubuntu 机器。
采纳答案by shoover
Does
做
uname -a
give you anything you can use? I don't have a 64-bit machine to test on.
给你什么你可以用？我没有要测试的 64 位机器。
Note from Mike Stone:This works, though specifically
迈克·斯通 (Mike Stone) 的笔记：虽然特别有效
uname -m
Will give "x86_64" for 64 bit, and something else for other 32 bit types (in my 32 bit VM, it's "i686").
将为 64 位提供“x86_64”，为其他 32 位类型提供其他信息（在我的 32 位 VM 中，它是“i686”）。
回答by bmdhacks
MACHINE_TYPE=`uname -m`
if [ ${MACHINE_TYPE} == 'x86_64' ]; then
# 64-bit stuff here
else
# 32-bit stuff here
fi
回答by Victor Zamanian
getconf LONG_BITseems to do the trick as well, which makes it even easier to check this since this returns simply the integer instead of some complicated expression.
getconf LONG_BIT似乎也能做到这一点，这使得检查这一点变得更加容易，因为它只返回整数而不是一些复杂的表达式。
if [ `getconf LONG_BIT` = "64" ]
then
echo "I'm 64-bit"
else
echo "I'm 32-bit"
fi
回答by lolesque
Be careful, in a chrooted 32-bit env, the uname is still answering like the 64-bit host system.
小心，在chrooted 32 位环境中，uname 仍然像 64 位主机系统一样回答。
getconf LONG_BITworks fine.
getconf LONG_BIT工作正常。
file /bin/cpor any well-known executable or library should do the trick if you don't have getconf (but you can store programs you can't use, and maybe there are not at this place).
file /bin/cp如果您没有 getconf，或者任何知名的可执行文件或库都应该可以解决问题（但您可以存储您无法使用的程序，也许这里没有）。
回答by inukaze
You can use , the follow script (i extract this from officially script of "ioquake3") : for example
您可以使用以下脚本（我从“ioquake3”的官方脚本中提取此脚本）：例如
archs=`uname -m`
case "$archs" in
i?86) archs=i386 ;;
x86_64) archs="x86_64 i386" ;;
ppc64) archs="ppc64 ppc" ;;
esac
for arch in $archs; do
test -x ./ioquake3.$arch || continue
exec ./ioquake3.$arch "$@"
done
==================================================================================
================================================== ================================
I'm making a script to detect the "Architecture", this is my simple code (I am using it with wine , for my Windows Games , under Linux , by each game , i use diferrent version of WineHQ, downloaded from "PlayOnLinux" site.
我正在制作一个脚本来检测“架构”，这是我的简单代码（我将它与 wine 一起使用，对于我的 Windows 游戏，在 Linux 下，每个游戏，我使用不同版本的 WineHQ，从“PlayOnLinux”下载地点。
# First Obtain "kernel" name
KERNEL=$(uname -s)
if [ $KERNEL = "Darwin" ]; then
KERNEL=mac
elif [ $Nucleo = "Linux" ]; then
KERNEL=linux
elif [ $Nucleo = "FreeBSD" ]; then
KERNEL=linux
else
echo "Unsupported OS"
fi
# Second get the right Arquitecture
ARCH=$(uname -m)
if [ $ARCH = "i386" ]; then
PATH="$PWD/wine/$KERNEL/x86/bin:$PATH"
export WINESERVER="$PWD/wine/$KERNEL/x86/bin/wineserver"
export WINELOADER="$PWD/wine/$KERNEL/x86/bin/wine"
export WINEPREFIX="$PWD/wine/data"
export WINEDEBUG=-all:$WINEDEBUG
ARCH="32 Bits"
elif [ $ARCH = "i486" ]; then
PATH="$PWD/wine/$KERNEL/x86/bin:$PATH"
export WINESERVER="$PWD/wine/$KERNEL/x86/bin/wineserver"
export WINELOADER="$PWD/wine/$KERNEL/x86/bin/wine"
export WINEPREFIX="$PWD/wine/data"
export WINEDEBUG=-all:$WINEDEBUG
ARCH="32 Bits"
elif [ $ARCH = "i586" ]; then
PATH="$PWD/wine/$KERNEL/x86/bin:$PATH"
export WINESERVER="$PWD/wine/$KERNEL/x86/bin/wineserver"
export WINELOADER="$PWD/wine/$Nucleo/x86/bin/wine"
export WINEPREFIX="$PWD/wine/data"
export WINEDEBUG=-all:$WINEDEBUG
ARCH="32 Bits"
elif [ $ARCH = "i686" ]; then
PATH="$PWD/wine/$KERNEL/x86/bin:$PATH"
export WINESERVER="$PWD/wine/$KERNEL/x86/bin/wineserver"
export WINELOADER="$PWD/wine/$KERNEL/x86/bin/wine"
export WINEPREFIX="$PWD/wine/data"
export WINEDEBUG=-all:$WINEDEBUG
ARCH="32 Bits"
elif [ $ARCH = "x86_64" ]; then
export WINESERVER="$PWD/wine/$KERNEL/x86_64/bin/wineserver"
export WINELOADER="$PWD/wine/$KERNEL/x86_64/bin/wine"
export WINEPREFIX="$PWD/wine/data"
export WINEDEBUG=-all:$WINEDEBUG
ARCH="64 Bits"
else
echo "Unsoportted Architecture"
fi
==================================================================================
================================================== ================================
Now i use this in my bash scripts , because works better in any distro .
现在我在我的 bash 脚本中使用它，因为在任何发行版中都能更好地工作。
# Get the Kernel Name
Kernel=$(uname -s)
case "$Kernel" in
Linux) Kernel="linux" ;;
Darwin) Kernel="mac" ;;
FreeBSD) Kernel="freebsd" ;;
* ) echo "Your Operating System -> ITS NOT SUPPORTED" ;;
esac
echo
echo "Operating System Kernel : $Kernel"
echo
# Get the machine Architecture
Architecture=$(uname -m)
case "$Architecture" in
x86) Architecture="x86" ;;
ia64) Architecture="ia64" ;;
i?86) Architecture="x86" ;;
amd64) Architecture="amd64" ;;
x86_64) Architecture="x86_64" ;;
sparc64) Architecture="sparc64" ;;
* ) echo "Your Architecture '$Architecture' -> ITS NOT SUPPORTED." ;;
esac
echo
echo "Operating System Architecture : $Architecture"
echo
回答by Kevin Little
slot8(msd):/opt # uname -a
Linux slot8a 2.6.21_mvlcge500-electra #1 SMP PREEMPT Wed Jun 18 16:29:33 \
EDT 2008 ppc64 GNU/Linux
Remember, there are other CPU architectures than Intel/AMD...
请记住，除了 Intel/AMD 之外，还有其他 CPU 架构......
回答by hoyhoy
You could do something like this:
你可以这样做：
if $(uname -a | grep 'x86_64'); then
echo "I'm 64-bit"
else
echo "I'm 32-bit"
fi
回答by hoyhoy
Yes, uname -ashould do the trick. see: http://www.stata.com/support/faqs/win/64bit.html.
是的，uname -a应该可以解决问题。请参阅：http: //www.stata.com/support/faqs/win/64bit.html。
