如何在按钮单击时打开布局（android）
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How to open layout on button click (android)
提问by Yusef Bee
How can I open another layout xml file when I click on a button in main.xml file?
当我单击 main.xml 文件中的按钮时，如何打开另一个布局 xml 文件？
so if I have main.xml which has a button sying click here and I click it, it opens up second.xml file (layout).
所以如果我有 main.xml 有一个按钮 sying click here 然后我点击它，它会打开 second.xml 文件（布局）。
回答by K_Anas
First Create your two layout:
首先创建你的两个布局：
main.xml
主文件
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:background="#ffffff" >
<TextView
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:textColor="#000000"
android:text="This is Activity 1" />
<Button android:text="Next"
android:id="@+id/Button01"
android:layout_width="250px"
android:textSize="18px"
android:layout_height="55px">
</Button>
</LinearLayout>
second.xml
第二个.xml
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:background="#ffffff" >
<TextView
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:textColor="#000000"
android:text="This is Activity 2" />
<Button android:text="Previous"
android:id="@+id/Button02"
android:layout_width="250px"
android:textSize="18px"
android:layout_height="55px">
</Button>
</LinearLayout>
Second Add your Activity to the manifest file
其次将您的活动添加到清单文件
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.rr"
android:versionCode="1"
android:versionName="1.0">
<application android:icon="@drawable/icon" android:label="@string/app_name">
<activity android:name=".Activity1"
android:label="@string/app_name">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<activity android:name=".Activity2"></activity>
</application>
<uses-sdk android:minSdkVersion="3" />
</manifest>
Activity1.java
Activity1.java
import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
public class Activity1 extends Activity {
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Button next = (Button) findViewById(R.id.Button01);
next.setOnClickListener(new View.OnClickListener() {
public void onClick(View view) {
Intent myIntent = new Intent(view.getContext(), Activity2.class);
startActivityForResult(myIntent, 0);
}
});
}
}
To switch to Activity2 you have to:
要切换到 Activity2，您必须：
Gets a reference to the button with ID Button01 on the layout using
(Button) findViewById(R.id.Button01).Create an OnClick listener for the button.
- And the most important part, creates an “Intent” to start another Activity. The intent needs two parameters: a context and the name of the Activity that we want to start (Activity2.class)
使用 获取对布局上 ID 为 Button01 的按钮的引用
(Button) findViewById(R.id.Button01)。为按钮创建一个 OnClick 侦听器。
- 最重要的部分是创建一个“意图”来启动另一个活动。Intent 需要两个参数：上下文和我们要启动的 Activity 的名称（Activity2.class）
Activity2.java
Activity2.java
import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
public class Activity2 extends Activity {
/** Called when the activity is first created. */
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.second);
Button next = (Button) findViewById(R.id.Button02);
next.setOnClickListener(new View.OnClickListener() {
public void onClick(View view) {
Intent intent = new Intent();
setResult(RESULT_OK, intent);
finish();
}
});
}
回答by Thkru
-Inflate the button from the xml
-add an onClickListener on it
-set a new layout in the onClick event
- 从 xml 中充气按钮 - 在其上
添加onClickListener
- 在 onClick 事件中设置新布局
Button btn = (Button) findViewById(R.id.myButton);
btn.setOnClickListener(new OnClickListener(){
@Override
public void onClick(View v)
{
MyActivity.setContentView(R.layout.newlayout);
}
});
Something like this should work...
像这样的东西应该工作......
回答by Fede Henze
A Kotlin way:
Kotlin 方式：
-Add the onClick event directly in the designer.
- 直接在设计器中添加 onClick 事件。
- Open the activity (Activity1.xml for example) file in the designer mode
- Select the button that will trigger the transition
- Add the function name on the onClick box of the right panel with all the button properties
- 在设计器模式下打开活动（例如Activity1.xml）文件
- 选择将触发过渡的按钮
- 在右侧面板的 onClick 框中添加函数名称以及所有按钮属性
-Open the Activity .kt file
- 打开活动 .kt 文件
Add the function with the name that you just defined in the designer
fun openActivity2(view: View) { intent = Intent(view.context,Activity2::class.java) startActivity(intent) }
使用您刚刚在设计器中定义的名称添加函数
fun openActivity2(view: View) { intent = Intent(view.context,Activity2::class.java) startActivity(intent) }
Now you have the function linked to the onClick event of your button
现在您已将函数链接到按钮的 onClick 事件
