node.js 将枚举转换为值数组（将所有 JSON 值放入数组中）
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Converting enums to array of values (Putting all JSON values in an array)
提问by Tolga E
I use this method Enums in JavaScript?to create enums in our code..
我在 JavaScript 中使用Enums方法吗？在我们的代码中创建枚举..
So
所以
var types = {
"WHITE" : 0,
"BLACK" : 1
}
Now the issue is when I want create validations anywhere, I have to do this;
现在的问题是当我想在任何地方创建验证时，我必须这样做；
model.validate("typesColumn", [ types.WHITE, types.BLACK ]);
Now is there a way I can just simple convert the values in types to an array so that I don't have to list all of the values of the enum?
现在有没有一种方法可以简单地将类型中的值转换为数组，这样我就不必列出枚举的所有值？
model.validate("typesColumn", types.ValuesInArray]);
EDIT: I created a very simple enum library to generate simple enums npm --save-dev install simple-enum(https://www.npmjs.com/package/simple-enum)
编辑：我创建了一个非常简单的枚举库来生成简单的枚举npm --save-dev install simple-enum（https://www.npmjs.com/package/simple-enum）
回答by Ali Soltani
Simple solution (ES6)
简单的解决方案 (ES6)
You can use Object.valueslike this:
你可以这样使用Object.values：
var valueArray = Object.values(types);
回答by Yann
I would convert the map into an array and store it as types.all.
You can create a method that does it automatically:
我会将地图转换为数组并将其存储为types.all. 您可以创建一个自动执行此操作的方法：
function makeEnum(enumObject){
var all = [];
for(var key in enumObject){
all.push(enumObject[key]);
}
enumObject.all = all;
}
回答by c.P.u1
var types = {
"WHITE" : 0,
"BLACK" : 1
}
var typeArray = Object.keys(types).map(function(type) {
return types[type];
});
//typeArray [0,1]
model.validate("typesColumn", typeArray);
回答by musefan
You could convert it to an array, or you can just iterate the properties of the object (which is how you would create the array anyway):
您可以将其转换为数组，或者您可以只迭代对象的属性（无论如何，这就是您创建数组的方式）：
for(var i in types){
var type = types[i];
//in the first iteration: i = "WHITE", type = 0
//in the second iteration: i = "BLACK", type = 1
}
Just for completeness, you can create the array with that method as follows:
为了完整起见，您可以使用该方法创建数组，如下所示：
var arr = [];
for(var i in types){
var type = types[i];
arr.push(type);
}
//arr = [0, 1]
to make this reusable you could create a helper function:
为了使其可重用，您可以创建一个辅助函数：
function ObjectToValueArray(obj){
var arr = [];
for(var i in obj){
var v = obj[i];
arr.push(v);
}
return arr;
}
Which can be called like so:
可以这样调用：
model.validate("typesColumn", ObjectToValueArray(types));
回答by Alex K.
Juice up (or wrap) .validatesuch that it will accept typesas meaning all members?
榨汁（或包装）.validate以便它接受types所有成员的意思？
var types = {
"WHITE" : 0,
"BLACK" : 1,
"RED" : 200
}
validate("foo", types.WHITE); // 0
validate("foo", [types.WHITE, types.BLACK]); // 0,1
validate("foo", types); // 0,1,200
function validate(foo, values) {
var arr = [];
switch (typeof values) {
case "number":
arr.push(values);
break;
case "object":
if (values instanceof Array)
arr = values;
else {
for (var k in values)
arr.push(values[k]);
}
break;
}
alert(arr);
}
