pandas 设置 seaborn 关节图的轴刻度值
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Setting the axes tick values of a seaborn jointplot
提问by Okechukwu Ossai
I'm trying to make the x and y axes (including axes tick values) of my jointplot to start and end with specific values and to be scaled in set increments.
我试图让我的关节图的 x 和 y 轴（包括轴刻度值）以特定值开始和结束，并以设定的增量进行缩放。
import pandas as pd
import numpy as np
import seaborn as sns
import matplotlib.pyplot as plt
g = sns.jointplot(x="LONGITUDE", y="LATITUDE", data=data,
kind='reg', color="#774499", dropna=True, size=7, space=0.3, ratio=5,
xlim=(-180,180), ylim=(-90,90), fit_reg=False);
plt.rc("legend", fontsize=15)
plt.xlabel('Longitude', fontsize=15)
plt.ylabel('Latitude', fontsize=15)
plt.title('Spatial Location Plot', fontsize=15 )
plt.tick_params(axis="both", labelsize=15)
Notice that the lower and upper edges of both axes do not have any tick values. I want the tick values to start and end at the axes edges using exactly the values I specified in xlim() and ylim().
请注意，两个轴的下边缘和上边缘都没有任何刻度值。我希望刻度值使用我在 xlim() 和 ylim() 中指定的值在轴边缘开始和结束。
My preferred increments are 90 and 45 degrees for the X and Y axes respectively. So, I want the X axis to look this: -180, -90, 0, 90, 180. And the Y axis to be: -90, -45, 0, 45, 90. Thanks for your suggestions.
我的首选增量分别是 X 和 Y 轴的 90 度和 45 度。所以，我希望 X 轴看起来像这样：-180、-90、0、90、180。Y 轴是：-90、-45、0、45、90。感谢您的建议。
采纳答案by tmdavison
You can use matplotlib.tickerto set the major_locatoron the axes. The JointGridreturned by jointplot(g) has a ax_jointattribute, which we can use to set the ticks. To set ticks every multiple of a number, we can use a MultipleLocator:
您可以使用matplotlib.ticker来设置major_locator轴上的 。将JointGrid通过返回jointplot（g）有一个ax_joint属性，我们可以用它来设置刻度。要设置数字的每个倍数的刻度，我们可以使用MultipleLocator：
import matplotlib.ticker as ticker
g.ax_joint.xaxis.set_major_locator(ticker.MultipleLocator(90))
g.ax_joint.yaxis.set_major_locator(ticker.MultipleLocator(45))
