你如何只从 python 日期时间中提取日期？
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How do you extract only the date from a python datetime?
提问by SZA
I have a dataframe in python. One of its columns is labelled time, which is a timestamp. Using the following code, I have converted the timestamp to datetime:
我在 python 中有一个数据框。其中一列标记为time，这是一个时间戳。使用以下代码，我已将时间戳转换为datetime：
milestone['datetime'] = milestone.apply(lambda x: datetime.datetime.fromtimestamp(x['time']), axis = 1)
Now I want to separate (tokenize) date and time and have two different columns like milestone['only_date']and milestone['only_time']. How do I do this?
现在我想分离（标记）日期和时间，并有两个不同的列，如milestone['only_date']和milestone['only_time']。我该怎么做呢？
采纳答案by julienc
You can use dateand timemethods of the datetimeclass to do so:
您可以使用类的date和time方法datetime来做到这一点：
>>> from datetime import datetime
>>> d = datetime.now()
>>> only_date, only_time = d.date(), d.time()
>>> only_date
datetime.date(2015, 11, 20)
>>> only_time
datetime.time(20, 39, 13, 105773)
Hereis the datetimedocumentation.
这是datetime文档。
Applied to your example, it can give something like this:
应用于您的示例，它可以给出如下内容：
>>> milestone["only_date"] = [d.date() for d in milestone["datetime"]]
>>> milestone["only_time"] = [d.time() for d in milestone["datetime"]]
