C++ 有没有办法用编译指示禁用所有警告？
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Is there a way to disable all warnings with a pragma?
提问by Ferruccio
I've started a new project and have decided to make sure it builds cleanly with the /Wall option enabled. The only problem is not all 3rd party libraries (like boost) compile without warnings, so I've resorted to doing this in a shared header:
我开始了一个新项目，并决定确保它在启用 /Wall 选项的情况下干净利落地构建。唯一的问题是并非所有 3rd 方库（如 boost）都可以在没有警告的情况下编译，所以我在共享头文件中执行此操作：
#pragma warning(push)
#pragma warning(disable:4820)
#pragma warning(disable:4619)
#pragma warning(disable:4668)
#pragma warning(disable:4625)
#pragma warning(disable:4626)
#pragma warning(disable:4571)
#pragma warning(disable:4347)
#pragma warning(disable:4640)
#pragma warning(disable:4365)
#pragma warning(disable:4710)
#pragma warning(disable:4820)
#pragma warning(disable:4350)
#pragma warning(disable:4686)
#pragma warning(disable:4711)
#pragma warning(disable:4548)
#include <boost/array.hpp>
#include <boost/assert.hpp>
#include <boost/assign.hpp>
#include <boost/bind.hpp>
#include <boost/lexical_cast.hpp>
#include <boost/filesystem.hpp>
#include <boost/foreach.hpp>
#include <boost/format.hpp>
#include <boost/function.hpp>
#include <boost/integer.hpp>
#include <boost/optional.hpp>
#include <boost/regex.hpp>
#include <boost/smart_ptr.hpp>
#include <boost/algorithm/string.hpp>
#include <boost/tuple/tuple.hpp>
#include <boost/utility.hpp>
#include <boost/variant.hpp>
#pragma warning(pop)
This works well enough, but every time I add new boost headers I have to add whatever warnings they generate to the list. Is there a way to say disable all warnings for this stretch of code?
这工作得很好，但每次我添加新的 boost 标头时，我都必须将它们生成的任何警告添加到列表中。有没有办法说禁用这段代码的所有警告？
回答by Assaf Lavie
You can push/pop a low level of warning, like this:
您可以推送/弹出低级别警告，如下所示：
#pragma warning(push, 0)
#include <boost/bind.hpp>
#include <boost/shared_ptr.hpp>
// ...
#pragma warning(pop)
But know that it's not possible to disable allwarnings. For example, some linker warnings are impossible to turn off.
但要知道不可能禁用所有警告。例如，某些链接器警告无法关闭。
回答by EvilTeach
#pragma warning(disable:4820)
#pragma warning(disable:4619)
#pragma warning(disable:4668)
for less lines....
对于更少的线路....
#pragma warning (disable : 4820 4619 4668)
回答by Matt Warren
What I've done before is set the "W3" option rather than "Wall" then in each of my own source .cpp files I put
我之前所做的是设置“W3”选项而不是“Wall”，然后在我放置的每个源 .cpp 文件中
#pragma warning(push, 4)
at the top AFTER all the "#include..." lines and then
在所有“#include ...”行之后的顶部，然后
#pragma warning(pop)
as the very last line of the file.
作为文件的最后一行。
This way you get level 4 warnings in your code and level 3 in 3rd party code that you can't do anything about.
通过这种方式，您会在代码中获得 4 级警告，在 3rd 方代码中获得 3 级警告，您对此无能为力。
回答by PolarBear
Using the technique described in the Assaf Lavie's answerit is possible to create helper macros:
使用Assaf Lavie 的回答中描述的技术，可以创建辅助宏：
#define DISABLE_ALL_WARNINGS_BEGIN \
__pragma(warning(push, 0))
#define DISABLE_ALL_WARNINGS_END \
__pragma(warning(pop))
They can be used in the following way (online demo):
它们可以通过以下方式使用（在线演示）：
DISABLE_ALL_WARNINGS_BEGIN
void foo(int a)
{
// this function should generate the following warning
// "warning C4100: 'a': unreferenced formal parameter"
// unless it is not wrapped inside "DISABLE_ALL_WARNINGS" section
}
DISABLE_ALL_WARNINGS_END
