通过 Java 复制 Zip 文件的最佳方式
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Best Way to copy a Zip File via Java
提问by bastianneu
After some research:
经过一番研究：
and some google research i came up with this java function:
和一些谷歌研究我想出了这个java函数：
static void copyFile(File zipFile, File newFile) throws IOException {
ZipFile zipSrc = new ZipFile(zipFile);
ZipOutputStream zos = new ZipOutputStream(new FileOutputStream(newFile));
Enumeration srcEntries = zipSrc.entries();
while (srcEntries.hasMoreElements()) {
ZipEntry entry = (ZipEntry) srcEntries.nextElement();
ZipEntry newEntry = new ZipEntry(entry.getName());
zos.putNextEntry(newEntry);
BufferedInputStream bis = new BufferedInputStream(zipSrc
.getInputStream(entry));
while (bis.available() > 0) {
zos.write(bis.read());
}
zos.closeEntry();
bis.close();
}
zos.finish();
zos.close();
zipSrc.close();
}
This code is working...but it is not nice and clean at all...anyone got a nice idea or an example?
这段代码正在运行......但它根本不漂亮和干净......有人有一个好主意或一个例子吗？
Edit:
编辑：
I want to able to add some type of validation if the zip archive got the right structure...so copying it like an normal file without regarding its content is not working for me...or would you prefer checking it afterwards...i am not sure about this one
如果 zip 存档具有正确的结构，我希望能够添加某种类型的验证......所以像普通文件一样复制它而不考虑其内容对我不起作用......或者你更愿意事后检查它......我不确定这个
回答by Fortega
You just want to copy the complete zip file? Than it is not needed to open and read the zip file... Just copy it like you would copy every other file.
您只想复制完整的 zip 文件？比它不需要打开和读取 zip 文件...只需像复制其他所有文件一样复制它。
public final static int BUF_SIZE = 1024; //can be much bigger, see comment below
public static void copyFile(File in, File out) throws Exception {
FileInputStream fis = new FileInputStream(in);
FileOutputStream fos = new FileOutputStream(out);
try {
byte[] buf = new byte[BUF_SIZE];
int i = 0;
while ((i = fis.read(buf)) != -1) {
fos.write(buf, 0, i);
}
}
catch (Exception e) {
throw e;
}
finally {
if (fis != null) fis.close();
if (fos != null) fos.close();
}
}
回答by miku
回答by Nishanth Thomas
My solution:
我的解决方案：
import java.io.*;
import javax.swing.*;
public class MovingFile
{
public static void copyStreamToFile() throws IOException
{
FileOutputStream foutOutput = null;
String oldDir = "F:/UPLOADT.zip";
System.out.println(oldDir);
String newDir = "F:/NewFolder/UPLOADT.zip"; // name as the destination file name to be done
File f = new File(oldDir);
f.renameTo(new File(newDir));
}
public static void main(String[] args) throws IOException
{
copyStreamToFile();
}
}
