Bash 脚本将文件名导出到变量
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Bash Scripting Export Filename to Variable
提问by Daven Patel
I'm trying to set a variable to a string representing a file's location and when I try to set the variable I keep on getting a 'permission denied' error, because the bash script is trying to execute the file.
我正在尝试将变量设置为表示文件位置的字符串，当我尝试设置该变量时，我不断收到“权限被拒绝”错误，因为 bash 脚本正在尝试执行该文件。
Here is the code I'm using
这是我正在使用的代码
date= 07062011
archive_dir=~/Documents/ABC/Testing
aggregate_file= `echo ${archive_dir}"/"${date}"_Aggregated.txt"`
The error I am getting is the following:
我得到的错误如下：
./8000.2146701.sh: line 32: /home/me/Documents/ABC/Testing/20110706_Aggregated.txt: Permission denied
./8000.2146701.sh：第 32 行：/home/me/Documents/ABC/Testing/20110706_Aggregated.txt：权限被拒绝
From what I understand using the backticks should allow me to take the output of the command and put it into a variable and it doesn't seem to be working. When I just do the echo statement by itself the output is the file path.
据我所知，使用反引号应该允许我获取命令的输出并将其放入一个变量中，但它似乎不起作用。当我自己执行 echo 语句时，输出是文件路径。
Thanks.
谢谢。
回答by DigitalRoss
The direct problem is the space following:
直接的问题是下面的空间：
aggregate_file=
That is:
那是：
aggregate_file= `echo ${archive_dir}"/"${date}"_Aggregated.txt"`
would have worked by simply removing the space after the assignment operator:
只需删除赋值运算符后的空格即可：
aggregate_file=`echo ${archive_dir}"/"${date}"_Aggregated.txt"`
But really it should have just been:
但实际上它应该是：
aggregate_file="${archive_dir}/${date}_Aggregated.txt"
回答by C. Ramseyer
Don't use backticks and echo, just aggregate_file="${archive_dir}/${date}_Aggregated.txt". And no spaces, as another poster mentioned.
不要使用反引号和回声，只是aggregate_file="${archive_dir}/${date}_Aggregated.txt". 正如另一张海报所提到的，没有空格。
