windows PowerShell - 从 URL 中不包含文件名的 URL 下载文件
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PowerShell - Download file(s) from URL that does not include file name in the URL
提问by Charles Feemster
I've searched around and tried a few things and have not gotten it to work.
The link would be for example: http://www.website com/file/[fileID](e.g. http://www.website com/file/1wA5fT) and a box would appear whether to save the file(s) or not.
我四处搜索并尝试了一些东西，但没有让它工作。链接将是例如：（http://www.website com/file/[fileID]例如http://www.website com/file/1wA5fT）并且会出现一个框是否保存文件。
I have tried this, from what I can remember and it did not work.
我已经尝试过这个，据我所知，它没有用。
$source = "http://www.website.com/file/[fileID]"
$dest = "C:\Users\Charles\Desktop\Downloads\"
$wc = New-Object System.Net.WebClient
$wc.DownloadFile($source, $dest)
Edit:
编辑：
I am able to correctly download the file if I put a filename for the destination. However I need to extract the filename from e.g.
如果我为目标输入文件名，我就可以正确下载文件。但是我需要从例如提取文件名
<a href="http://www.website.com/file/[fileID]">Filename.txt</a></li></div></ul>
<a href="http://www.website.com/file/[fileID]">Filename.txt</a></li></div></ul>
After I get this singled out how would I single out the filename into $Filename?
在我挑出这个之后，我将如何将文件名挑出到 $Filename 中？
$source = "http://www.website.com/file/[fileID]"
$dest = "C:\Users\Charles\Desktop\Downloads$Filename"
$wc = New-Object System.Net.WebClient
$wc.DownloadFile($source, $dest)
This code would work then.
这段代码然后就可以工作了。
回答by Bob Reynolds
$source = "http://www.website.com/file/someFile.txt"
$Filename = [System.IO.Path]::GetFileName($source)
$dest = "C:\Users\Charles\Desktop\Downloads$Filename"
$wc = New-Object System.Net.WebClient
$wc.DownloadFile($source, $dest)
回答by toftis
I got the same error as you described when I called:
我在打电话时遇到了与您描述的相同的错误：
$source = "http://www.website.com/file/[fileID]"
$dest = "C:\Users\Charles\Desktop\Downloads\"
$wc = New-Object System.Net.WebClient
$wc.DownloadFile($source, $dest)
But when I changed $dest to contain the full path(including the name of the file it worked)
但是当我将 $dest 更改为包含完整路径时（包括它工作的文件名）
$dest = "C:\Users\Charles\Desktop\Downloads\[aFileName]"
