Python 存储在元组中的元素总和
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Sum of elements stored inside a tuple
提问by Manas Chaturvedi
Given a tuple containing a bunch of integer elements, how can one find the sum of all the elements?
给定一个包含一堆整数元素的元组，如何找到所有元素的总和？
For example, if I have a list of tuples:
例如，如果我有一个元组列表：
li = [(1, 2), (1, 3), (2, 3)]
How can I get something like this:
我怎样才能得到这样的东西：
[3, 4, 5]
where 3, 4 and 5 is the total sum of each of the three tuples respectively?
其中 3、4 和 5 分别是三个元组中每个元组的总和？
采纳答案by thefourtheye
You can use mapand sumfunction like this
>>> li = [(1, 2), (1, 3), (2, 3)]
>>> map(sum, li)
[3, 4, 5]
Alternatively you can use list comprehension, like this
或者，您可以使用列表理解，就像这样
>>> [sum(tup) for tup in li]
[3, 4, 5]
Note:I personally prefer the list comprehension version, because mapfunction in Python 3.x will return an iterable mapobject, which needs to be explicitly converted to a list, like this list(map(sum, li)).
注意：我个人更喜欢列表推导式版本，因为mapPython 3.x 中的函数将返回一个可迭代map对象，该对象需要显式转换为列表，如下所示list(map(sum, li))。
>>> li = [(1, 2), (1, 3), (2, 3)]
>>> map(sum, li)
<map object at 0x7f3dc25bb0f0>
>>> type(map(sum, li))
<class 'map'>
>>> list(map(sum, li))
[3, 4, 5]
But list comprehension will give a list in both Python 2.x and Python 3.x.
但是列表理解将在 Python 2.x 和 Python 3.x 中给出一个列表。
回答by Avinash Raj
You could use list comprehension.
您可以使用列表理解。
>>> li = [(1, 2), (1, 3), (2, 3)]
>>> [x+y for (x,y) in li]
[3, 4, 5]
回答by Vivek Sable
For beginner:
初学者：
- Create result variable which type is list.
- Iterate every item from the give list by
forloop. - As every item is tuple so again iterate item from the step 2 and set sum of item to 0.
- Add sum.
- Append sum to result variable.
- 创建类型为列表的结果变量。
- 通过循环迭代给定列表中的每个项目
for。 - 由于每个项目都是元组，因此再次从步骤 2 迭代项目并将项目总和设置为 0。
- 加总。
- 将 sum 附加到结果变量。
Demo:
演示：
>>> li = [(1, 2), (1, 3), (2, 3)] # Given Input
>>> result = [] # Step 1
>>> for i in li: # Step 2
... tmp_sum = 0 # Step 3
... for j in i: # Step 3
... tmp_sum += j # Step 4
... result.append(tmp_sum) # Step 5
...
>>> print result
[3, 4, 5]
回答by Kishor Subedi
ls= [(1,2), (3,4)]
finallist = []
for tuple in ls:
listt = list(tuple)
summ = 0
for m in listt:
summ+=m
finallist.append(summ)
print(finallist) #[3,7]
回答by JAID
Both solutions below will work.
下面的两种解决方案都有效。
li = [(1, 2), (1, 3), (2, 3)]
print([sum(i) for i in li])
or
或者
def sumtupleinlist(lst):
return [sum(i) for i in lst]
li = [(1, 2), (1, 3), (2, 3)]
To test the function, run :
要测试该功能，请运行：
print(sumtupleinlist(li))
