bash 如何使用 sed 在一行后插入换行符/换行符
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How do I insert a newline/linebreak after a line using sed
提问by realityloop
It took me a while to figure out how to do this, so posting in case anyone else is looking for the same.
我花了一段时间才弄清楚如何做到这一点，所以发布以防其他人正在寻找相同的内容。
回答by devnull
For adding a newline after a pattern, you can also say:
要在模式后添加换行符，您还可以说：
sed '/pattern/{G;}' filename
Quoting GNU sed manual:
引用GNU sed 手册：
G
Append a newline to the contents of the pattern space, and then append the contents of the hold space to that of the pattern space.
EDIT:
编辑：
Incidentally, this happens to be covered in sed one liners:
顺便说一句，这恰好包含在sed one liners 中：
# insert a blank line below every line which matches "regex"
sed '/regex/G'
回答by realityloop
This sed command:
这个 sed 命令：
sed -i '' '/pid = run/ a\
\
' file.txt
Finds the line with: pid = run
查找具有以下内容的行：pid = run
file.txt before
之前的文件.txt
; Note: the default prefix is /usr/local/var
; Default Value: none
;pid = run/php-fpm.pid
; Error log file
and adds a linebreak after that line inside file.txt
并在 file.txt 中的那一行之后添加一个换行符
file.txt after
文件.txt之后
; Note: the default prefix is /usr/local/var
; Default Value: none
;pid = run/php-fpm.pid
; Error log file
Or if you want to add text and a linebreak:
或者，如果您想添加文本和换行符：
sed -i '/pid = run/ a\
new line of text\
' file.txt
file.txt after
文件.txt之后
; Note: the default prefix is /usr/local/var
; Default Value: none
;pid = run/php-fpm.pid
new line of text
; Error log file
回答by Richard
A simple substitution works well:
一个简单的替换效果很好：
sed 's/pattern.*$/&\n/'
Example :
例子 ：
$ printf "Hi\nBye\n" | sed 's/H.*$/&\nJohn/'
Hi
John
Bye
To be standard compliant, replace \n by backslash newline :
要符合标准，请将 \n 替换为反斜杠换行符：
$ printf "Hi\nBye\n" | sed 's/H.*$/&\
> John/'
Hi
John
Bye
回答by nemo
sed '/pattern/a\r' file name
It will add a return after the pattern while gwill replace the pattern with a blank line.
它将在模式后添加一个返回，同时g将用空行替换模式。
If a new line (blank) has to be added at end of the file use this:
如果必须在文件末尾添加新行（空白），请使用以下命令：
sed '$a\r' file name
回答by Gerald Schade
Another possibility, e.g. if You don't have an empty hold register, could be:
另一种可能性，例如，如果您没有空的保留寄存器，则可能是：
sed '/pattern/{p;s/.*//}' file
Explanation:/pattern/{...}= apply sequence of commands, if line with pattern found,p= print the current line,;= separator between commands,s/.*//= replace anything with nothing in the pattern register,
then automatically print the empty pattern register as additional line)
说明：/pattern/{...}= 应用命令序列，如果找到具有模式的行，p= 打印当前行，;= 命令之间的分隔符，s/.*//= 用模式寄存器中的任何内容替换任何内容，
然后自动将空模式寄存器打印为附加行）
