C++ 如何获取放置在 MFC 对话框中的控件的大小和位置？
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How to get size and location of a control placed on a dialog in MFC?
提问by dragan.stepanovic
I've got the pointer to the control with function
我有指向带有函数的控件的指针
CWnd* CWnd::GetDlgItem(int ITEM_ID)
so i've got CWnd*pointer which points to the control,
but simply can't find any method within CWndclass that will
retrieve the size and location of a given control.
Any help?
所以我有CWnd*指向控件的指针，但在CWnd类中根本找不到任何方法来检索给定控件的大小和位置。有什么帮助吗？
回答by interjay
CRect rect;
CWnd *pWnd = pDlg->GetDlgItem(YOUR_CONTROL_ID);
pWnd->GetWindowRect(&rect);
pDlg->ScreenToClient(&rect); //optional step - see below
//position: rect.left, rect.top
//size: rect.Width(), rect.Height()
GetWindowRectgives the screen coordinates of the control. pDlg->ScreenToClientwill then convert them be relative to the dialog's client area, which is usually what you need.
GetWindowRect给出控件的屏幕坐标。pDlg->ScreenToClient然后将它们转换为相对于对话框的客户区，这通常是您需要的。
Note: pDlgabove is the dialog. If you're in a member function of the dialog class, just remove the pDlg->.
注意：pDlg上面是对话框。如果您在对话框类的成员函数中，只需删除pDlg->.
回答by Jason Newland
In straight MFC/Win32: (Example of WM_INITDIALOG)
在直接 MFC/Win32 中：（WM_INITDIALOG 示例）
RECT r;
HWND h = GetDlgItem(hwndDlg, IDC_YOURCTLID);
GetWindowRect(h, &r); //get window rect of control relative to screen
POINT pt = { r.left, r.top }; //new point object using rect x, y
ScreenToClient(hwndDlg, &pt); //convert screen co-ords to client based points
//example if I wanted to move said control
MoveWindow(h, pt.x, pt.y + 15, r.right - r.left, r.bottom - r.top, TRUE); //r.right - r.left, r.bottom - r.top to keep control at its current size
Hope this helps! Happy coding :)
希望这可以帮助！快乐编码:)
