Python os.path.split，在不影响路径的情况下更改文件名
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os.path.split, changing file name with out compromising the Path
提问by ashir nasir
i have followed Python get file name and change & save it in variable. which work fine and change the file name as required.
我已经按照Python 获取文件名并更改并将其保存在变量中。工作正常并根据需要更改文件名。
but now i am facing problem with path where the file is getting saved. as the file is getting saved in "media/ok_abc.txt" whereas it should be media/documents/ok_abc.txt
但现在我面临文件保存路径的问题。因为文件被保存在“ media/ok_abc.txt”中，而它应该是media/documents/ok_abc.txt
e.g.
例如
docfile = /media/documents/abc.csv after applaying below instruction
docfile = /media/documents/abc.csv 应用以下指令后
filename = os.path.splitext(docfile.name)[0]
newfilename = 'ok_%s.txt' % filename
am able to change the file name but the path is getting reduced as /media/ok_abc.txt, it should be /media/documents/abc.txt
我能够更改文件名，但路径越来越少，为/media/ok_abc.txt，它应该是/media/documents/abc.txt
how i can change the file name with out compromising on the Path
如何在不影响路径的情况下更改文件名
回答by ledzep2
Extract the directory from the full file path, and later add it back.
从完整文件路径中提取目录，然后将其添加回来。
path, filename = os.path.split(docfile)
filename = os.path.splitext(filename)[0]
newfilename = 'ok_%s.txt' % filename
newpath = os.path.join(path, newfilename)
