bash 如何使用 sed 用 \(space) 替换空格？
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How to replace space with \(space) using sed?
提问by Somenath Sinha
When I use sed to replace all the spaces with X, the command works, the command being:
当我使用 sed 用 X 替换所有空格时，命令有效，命令为：
sed 's/ /X/g' filelist.tmp
However, when I try the same to replace all occurrences of space with \space, the code being :
但是，当我尝试用 \space 替换所有出现的空格时，代码为：
sed 's/ /\ /g' filelist.tmp
It doesn't work. What am I doing wrong? Note that I'm new to shell scripting.
它不起作用。我究竟做错了什么？请注意，我是 shell 脚本的新手。
回答by heemayl
Add another \i.e. you need to make \literal:
添加另一个\即你需要使\文字：
sed 's/ /\ /g'
With only a single \before space, the \is escaping the following space; as the space is not a special character in replacement that needs escaping, it is being taken as is.
\前面只有一个空格， the\正在转义后面的空格；由于空格不是需要转义的替换中的特殊字符，因此按原样使用。
Example:
例子：
% sed 's/ /\ /g' <<<'foo bar spam'
foo\ \ bar\ \ spam
回答by Daniel
You should use -r argument and should fix syntax to
您应该使用 -r 参数并且应该将语法修复为
sed -r "s/\s/\\s/g" filelist.tmp
You have mistake in order of escaping "\" also.
您在转义“\”的顺序上也有错误。
