创建 bash 脚本以从现有的 linux etc/hosts 文件创建 yaml 文件
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Create bash script to create yaml files from existing linux etc/hosts files
提问by atomicsitup
I'm new to scripting but have been tasked with creating yaml files from existing Linux /etc/hosts files. Using a hosts file here:
我是脚本的新手，但我的任务是从现有的 Linux /etc/hosts 文件创建 yaml 文件。在此处使用主机文件：
127.0.0.1 localhost
192.168.1.2 host1
192.168.1.3 host2
192.168.1.4 host3
192.168.1.5 host4
..to create yaml files that look like this:
..创建如下所示的 yaml 文件：
host_entries:
host1:
ip: '192.168.1.2'
host2:
ip: '192.168.1.3'
host3:
ip: '192.168.1.4'
host4:
ip: '192.168.1.5'
I know there is more than one way to reach a desired solution. But I'm not quite sure how to script this in a way to get the correct format. Any suggestions would be appreciated.
我知道有不止一种方法可以达到所需的解决方案。但我不太确定如何以某种方式编写脚本以获得正确的格式。任何建议，将不胜感激。
回答by Charles Duffy
Easy and wrong (not strongly guaranteed that output will be valid YAML for all possible inputs):
简单和错误（不强烈保证输出对于所有可能的输入都是有效的 YAML）：
{
printf 'host_entries:\n'
while read -r -a line; do
[[ ${line[0]} ]] || continue # skip blank lines
[[ ${line[0]} = "#"* ]] && continue # skip comments
[[ ${line[0]} = 127.0.0.1 ]] && continue # skip localhost
set -- "${line[@]}" # assign words read from line to current argument list
ip=; shift # assign first word from line to ip
for name; do # iterate over other words, treating them as names
printf " %s:\n ip: '%s'\n" "$name" "$ip"
done
done
} </etc/hosts >yourfile.yaml
...for something that's shorter and wrong-er, see edit history (prior version also worked for your sample input, but couldn't correctly handle blank lines, comments, IPs with more than one hostname, etc).
...对于较短和错误的内容，请参阅编辑历史记录（先前版本也适用于您的示例输入，但无法正确处理空行、注释、具有多个主机名的 IP 等）。
Given your exact host file as input, this emits:
将您的确切主机文件作为输入，这会发出：
host_entries:
host1:
ip: '192.168.1.2'
host2:
ip: '192.168.1.3'
host3:
ip: '192.168.1.4'
host4:
ip: '192.168.1.5'
