PHP:DomElement->getAttribute

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/2327429/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-08-25 06:03:38  来源:igfitidea点击:

PHP: DomElement->getAttribute

phpdomdomdocument

提问by Loreto Gabawa Jr.

How can I take all the attribute of an element? Like on my example below I can only get one at a time, I want to pull out all of the anchor tag's attribute.

如何获取元素的所有属性?就像在下面的示例中,我一次只能获取一个,我想提取所有锚标记的属性。

$dom = new DOMDocument();
@$dom->loadHTML(http://www.example.com);

$a = $dom->getElementsByTagName("a");
echo $a->getAttribute('href');

thanks!

谢谢!

回答by Simon

$length = $a->attributes->length;
$attrs = array();
for ($i = 0; $i < $length; ++$i) {
    $name = $a->attributes->item($i)->name;
    $value = $a->getAttribute($name);

    $attrs[$name] = $value;
}


print_r($attrs);

回答by middus

"Inspired" by Simon's answer. I think you can cut out the getAttributecall, so here's a solution without it:

受西蒙的回答“启发”。我认为你可以切断getAttribute电话,所以这里有一个没有它的解决方案:

$attrs = array();
for ($i = 0; $i < $a->attributes->length; ++$i) {
  $node = $a->attributes->item($i);
  $attrs[$node->nodeName] = $node->nodeValue;
}
var_dump($attrs);

回答by a1ex07

$a = $dom->getElementsByTagName("a");
foreach($a as $element)
{
   echo $element->getAttribute('href');
}

回答by pdchaudhary

$html = $data['html'];
if(!empty($html)){
   $doc = new DOMDocument();
   $doc->loadHTML($html);
   $doc->saveHTML();
   $datadom = $doc->getElementsByTagName("input");
   foreach($datadom as $element)
   {
       $class =$class." ".$element->getAttribute('class');
   }
}