ios 查找字符串中某个字符的索引
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Find the index of a character in a string
提问by fadd
I have a string NSString *Original=@"88) 12-sep-2012";or Original=@"8) blablabla";
我有一个字符串NSString *Original=@"88) 12-sep-2012";或Original=@"8) blablabla";
I want to print only the characters before the ")" so how to find the index of the character ")". or how could i do it?
我只想打印“)”之前的字符，那么如何找到字符“)”的索引。或者我怎么做？
Thanks in advance.
提前致谢。
回答by Padavan
To print the characters before the first right paren, you can do this:
要在第一个右括号之前打印字符，您可以执行以下操作：
NSString *str = [[yourString componentsSeparatedByString:@")"] objectAtIndex:0];
NSLog(@"%@", str);
// If you need the character index:
NSUInteger index = str.length;
回答by Paresh Navadiya
U can find index of the character ")" like this:
你可以像这样找到字符“)”的索引：
NSString *Original=@"88) 12-sep-2012";
NSRange range = [Original rangeOfString:@")"];
if(range.location != NSNotFound)
{
NSString *result = [Original substringWithRange:NSMakeRange(0, range.location)];
}
回答by Vimal Venugopalan
You can use the following code to see the characters before ")"
可以使用以下代码查看“)”前的字符
// this would split the string into values which would be stored in an array
NSArray *splitStringArray = [yourString componentsSeparatedByString:@")"];
// this would display the characters before the character ")"
NSLog(@"%@", [splitStringArray objectAtIndex:0]);
回答by freestyler
NSUInteger index = [Original rangeOfString:@")"];
NSString *result = [Original substringWithRange:NSMakeRange(0, index)];
回答by Ravi Sharma
try the below code to get the index of a particular character in a string:-
尝试以下代码以获取字符串中特定字符的索引：-
NSString *string = @"88) 12-sep-2012";
NSCharacterSet *charSet = [NSCharacterSet characterSetWithCharactersInString:@")"];
NSRange range = [string rangeOfCharacterFromSet:charSet];
if (range.location == NSNotFound)
{
// ... oops
}
else {
NSLog(@"---%d", range.location);
// range.location is the index of character )
}
and to get the string before the ) character use this:-
并在 ) 字符之前获取字符串，请使用：-
NSString *str = [[string componentsSeparatedByString:@")"] objectAtIndex:0];
回答by Gloomcore
Another soluation:
另一个解决方案：
NSString *Original=@"88) 12-sep-2012";
NSRange range = [Original rangeOfString:@")"];
NSString *result = Original;
if (range.location != NSNotFound)
{
result = [Original substringToIndex:range.location];
}
NSLog(@"Result: %@", result);
