C语言 在 C 中打印结构
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Print a struct in C
提问by Albus Dumbledore
I am trying to print a structthat is coming as an argument in a function in order to do some debugging.
我正在尝试打印struct作为函数中的参数出现的一个，以便进行一些调试。
Is there anyway I could print a structure's contents without knowing what it looks like, i.e. without printing each field explicitly? You see, depending on loads of different #defines the structure may look very differently, i.e. may have or not have different fields, so I'd like to find an easy way to do something like print_structure(my_structure).
无论如何我可以在不知道结构的内容的情况下打印它的内容，即无需明确打印每个字段？你看，根据不同#defines 的负载，结构可能看起来非常不同，即可能有或没有不同的字段，所以我想找到一种简单的方法来做类似的事情print_structure(my_structure)。
NetBeans' debugger can do that for me, but unfortunately the code is running on a device I can't run a debugger on.
NetBeans 的调试器可以为我做到这一点，但不幸的是代码在我无法运行调试器的设备上运行。
Any ideas? I suppose it's not possible, but at least there may be some macro to do that at compilation time or something?
有任何想法吗？我想这是不可能的，但至少在编译时可能有一些宏可以做到这一点？
Thanks!
谢谢！
回答by Fred Foo
You can always do a hex dump of the structure:
您始终可以对结构进行十六进制转储：
#define PRINT_OPAQUE_STRUCT(p) print_mem((p), sizeof(*(p)))
void print_mem(void const *vp, size_t n)
{
unsigned char const *p = vp;
for (size_t i=0; i<n; i++)
printf("%02x\n", p[i]);
putchar('\n');
};
回答by pma_
There is nothing like RTTI in C, only solution (apart from hex dump like above) is to #define dump function together with other #defines, ie.
C 中没有像 RTTI 那样的东西，唯一的解决方案（除了上面的十六进制转储）是#define 转储函数与其他 #defines 一起，即。
#if _DEBUG
struct { ..... }
#define STRUCT_DUMP(x) printf(.....)
#else
struct { ..... } // other version
#define STRUCT_DUMP(x) printf(.....) // other version dump
#endif
