php 提交后成功/失败消息弹出框?

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时间:2020-08-25 10:46:07  来源:igfitidea点击:

successful/fail message pop up box after submit?

phpjavascript

提问by munue

Basically after clicking the submit button, I want a pop up box to pop up saying successful or fail, then clicking OK to confirm the message. At the moment i am getting a pop up box "undefined" followed by failed message pop up box. HELP PLEASE!

基本上在单击提交按钮后,我想要一个弹出框弹出说成功或失败,然后单击确定以确认消息。目前我收到一个弹出框“未定义”,然后是失败的消息弹出框。 请帮忙!

here is the script

这是脚本

<?php
include ('config.php');

if (isset($_POST['name'])) {

$name = "name";

$query = "INSERT INTO pop ('id','name') VALUES ('','$name')";
    $result = mysql_query($query,$cn);
    if ($result) {
    echo "<script type='text/javascript'>alert('submitted successfully!')</script>";
}
else
{
    echo "<script type='text/javascript'>alert('failed!')</script>";
}
}       
?>

<html>
<head>
</head>
<body>

    <form action="" method="post">
    Name:<input type="text" id="name" name="name"/>
    <input type="submit" value="submit" name="submit" onclick="alert();"/>
    </form>
</body>

回答by DannyB

You are echoing outside the body tag of your HTML. Put your echos there, and you should be fine.

您正在 HTML 的 body 标记之外进行回显。把你的回声放在那里,你应该没问题。

Also, remove the onclick="alert()"from your submit. This is the cause for your first undefinedmessage.

另外,onclick="alert()"从您的提交中删除。这是您undefined发送第一条消息的原因。

<?php
  $posted = false;
  if( $_POST ) {
    $posted = true;

    // Database stuff here...
    // $result = mysql_query( ... )
    $result = $_POST['name'] == "danny"; // Dummy result
  }
?>

<html>
  <head></head>
  <body>

  <?php
    if( $posted ) {
      if( $result ) 
        echo "<script type='text/javascript'>alert('submitted successfully!')</script>";
      else
        echo "<script type='text/javascript'>alert('failed!')</script>";
    }
  ?>
    <form action="" method="post">
      Name:<input type="text" id="name" name="name"/>
      <input type="submit" value="submit" name="submit"/>
    </form>
  </body>
</html>

回答by half-fast

Instead of using a submit button, try using a <button type="button">Submit</button>

不要使用提交按钮,而是尝试使用 <button type="button">Submit</button>

You can then call a javascript function in the button, and after the alert popup is confirmed, you can manually submit the form with document.getElementById("form").submit(); ... so you'll need to name and id your form for that to work.

然后就可以在按钮中调用一个javascript函数,确认弹出alert后,就可以用document.getElementById("form").submit();手动提交表单了。...所以你需要命名和标识你的表单才能工作。