Linux 如何使用bash对文件夹中的文件进行排序？
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How to sort files in a folder using bash?
提问by wakandan
I have these files in a folder:
我在一个文件夹中有这些文件：
chap11-solutions.pdf
chap12-solutions.pdf
chap13-solutions.pdf
chap14-solutions.pdf
chap15-solutions.pdf
chap16-solutions.pdf
chap17-solutions.pdf
chap21-solutions.pdf
chap22-solutions.pdf
chap23-solutions.pdf
chap24-solutions.pdf
chap25-solutions.pdf
chap26-solutions.pdf
chap2-solutions.pdf
chap3-solutions.pdf
chap4-solutions.pdf
chap5-solutions.pdf
chap6-solutions.pdf
chap7-solutions.pdf
chap8-solutions.pdf
chap9-solutions.pdf
how do I sort them in this way: chap1..., chap...2, ...., chap11..., chap12,... using Ubuntu bash shell? Thanks.
我如何以这种方式对它们进行排序： chap1..., chap...2, ...., chap11..., chap12,... 使用 Ubuntu bash shell？谢谢。
采纳答案by Arnaud Le Blanc
ls|sort -V
The -Vparameter ensures that chap10is considered upper that chap9.
该-V参数确保chap10被认为高于chap9。
回答by mpenkov
Assuming that you want to rename the files so you don't have to keep sorting them later:
假设您要重命名文件，以便以后不必继续对它们进行排序：
for f in chap*-solutions.pdf; do num=`echo $f | grep -o "[0123456789]\+"`; two_num=`printf "%02d" $num`; mv $f chap$two_num-solutions.pdf; done
grep -o "[0123456789]+"outputs the chapter number (one or two digits)printfreturns a string that contains the zero-padded number
grep -o "[0123456789]+"输出章节编号（一位或两位数字）printf返回一个包含零填充数字的字符串
回答by kurumi
If you have ruby(1.9.1+)
如果你有红宝石（1.9.1+）
ruby -e 'puts Dir["chap*pdf"].sort_by{|x|x[/\d+/].to_i}'
回答by Paused until further notice.
GNU lshas a version sort built-in:
GNUls有一个内置的版本排序：
ls -lv
