pandas 类型错误：无法解包不可迭代的 int 对象
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TypeError: cannot unpack non-iterable int objec
提问by user11036847
how can I solve this error After running my code as follows . I am using the function below and implementin running window for loop on it but end up getting the error below. The for loop works and hungs at a point.
我如何解决这个错误运行我的代码如下。我正在使用下面的函数并在运行窗口中实现循环，但最终得到以下错误。for 循环起作用并挂在某个点上。
def get_grps(s, thresh=-1, Nmin=3):
"""
Nmin : int > 0
Min number of consecutive values below threshold.
"""
m = np.logical_and.reduce([s.shift(-i).le(thresh) for i in range(Nmin)])
if Nmin > 1:
m = pd.Series(m, index=s.index).replace({False: np.NaN}).ffill(limit=Nmin - 1).fillna(False)
else:
m = pd.Series(m, index=s.index)
# Form consecutive groups
gps = m.ne(m.shift(1)).cumsum().where(m)
# Return None if no groups, else the aggregations
if gps.isnull().all():
return 0
else:
agg = s.groupby(gps).agg([list, sum, 'size']).reset_index(drop=True)
# agg2 = s2.groupby(gps).agg([list, sum, 'size']).reset_index(drop=True)
return agg, gps
data_spi = [-0.32361498 -0.5229471 0.15702732 0.28753752 -0.01069884 -0.8163699
-1.3169327 0.4413181 0.75815576 1.3858147 0.49990863-0.06357133
-0.78432 -0.95337325 -1.663739 0.18965477 0.81183237 0.8360347
0.99537593 -0.12197364 -0.31432647 -2.0865853 0.2084263 0.13332903
-0.05270813 -1.0090573 -1.6578217 -1.2969246 -0.70916456 0.70059913
-1.2127264 -0.659762 -1.1612778 -2.1216285 -0.8054617 -0.6293912
-2.2103117 -1.9373081 -2.530625 -2.4089663 -1.950846 -1.6129876]
lon = data_spi.lon
lat = data_spi.lat
print(len(data_spi))
n=6
for x in range(len(lat)):
for y in range(len(lon)):
if data_spi[0, x, y] != 0:
for i in range(len(data_spi)-70):
ts = data_spi[i:i+10, x, y].fillna(1)
print(ts)
# print(np.array(ts))
agg, gps = get_grps(pd.Series(ts), thresh=-1, Nmin=3)
duration = np.nanmean(agg['sum'])
frequency = len(agg['sum'])
severity = np.abs(np.mean(agg['sum']))
intensity = np.mean(np.abs(agg['sum'] / agg['size']))
print(f'intensity {intensity}')
I get this error
我收到这个错误
Traceback (most recent call last):
File "/Users/mada0007/PycharmProjects/Research_ass /FREQ_MEAN_INT_DUR_CORR.py", line 80, in <module>
agg, gps = get_grps(pd.Series(ts), thresh=-1, Nmin=3)
typeError: cannot unpack non-iterable int object
How can I resolve this error ?
我该如何解决这个错误？
回答by olinox14
Just replace return 0 by return 0, 0, or better: raise an error instead of returning 0
只需将 return 0 替换为 return 0、0 或更好：引发错误而不是返回 0
When your ifcondition is True, you only return 0. Then later, when you do agg, gps = get_grps(...), you tell python to unpack the result of the function. Then, python is expecting a 2-length iterable, and try to unpack it, but as it says: it 'cannot unpack non-iterable int object'...
当您的if条件为 True 时，您只返回0。然后，当你这样做时agg, gps = get_grps(...)，你告诉 python 解包函数的结果。然后，python 期待一个 2 长度的可迭代对象，并尝试解压缩它，但正如它所说：它“无法解压缩不可迭代的 int 对象”......
So a quick workaround is to return a tuple (0, 0) with return 0, 0, but it is quite bad because you return integers where objects are expected. your script will crash on the next line duration = np.nanmean(agg['sum'])(since aggis 0).
所以一个快速的解决方法是用 返回一个元组 (0, 0) return 0, 0，但它很糟糕，因为你在预期对象的地方返回整数。您的脚本将在下一行崩溃duration = np.nanmean(agg['sum'])（因为agg是 0）。
Some cleaner solutions to handle this case would be to unpack in a second time:
处理这种情况的一些更清洁的解决方案是再次打开包装：
def get_grps(s, thresh=-1, Nmin=3):
# ...
if gps.isnull().all():
return None
else:
# ...
return agg, gps
for i in range(len(data_spi)-70):
ts = data_spi[i:i+10, x, y].fillna(1)
result = get_grps(pd.Series(ts), thresh=-1, Nmin=3)
if result is None:
break
agg, gps = result
duration = np.nanmean(agg['sum'])
frequency = len(agg['sum'])
