是否可以在 C# 中创建一个新的运算符？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/1040114/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Is it possible to create a new operator in c#?
提问by Aaron Palmer
I know you can overload an existing operator. I want to know if it is possible to create a new operator. Here's my scenario.
我知道您可以重载现有的运算符。我想知道是否可以创建一个新的运算符。这是我的场景。
I want this:
我要这个：
var x = (y < z) ? y : z;
To be equivalent to this:
相当于：
var x = y <? z;
In other words, I would like to create my own <?operator.
换句话说，我想创建自己的<?运算符。
采纳答案by AgileJon
No, it is not possible. You would need to create a method instead
不，这是不可能的。您需要创建一个方法
回答by Dario
No, but you can overload some existing operatorsin C#.
不，但您可以在 C# 中重载一些现有的运算符。
In some other languages, like F#, you can use:
在其他一些语言（如 F#）中，您可以使用：
let (<?) = min
回答by David Z
As the other answers have said, you can't create a new operator - at least, not without altering the lexer and parser that are built into the compiler. Basically, the compiler is built to recognize that an individual character like <or ?, or a pair like >>or <=, is an operator and to treat it specially; it knows that i<5is an expression rather than a variable name, for instance. Recognizing an operator as an operator is a separate process from deciding what the operator actually does, and is much more tightly integrated into the compiler - which is why you can customize the latter but not the former.
正如其他答案所说，你不能创建一个新的运算符 - 至少，在不改变编译器内置的词法分析器和解析器的情况下不能。基本上，编译器被构建为识别像<or?或一对像>>or这样的单个字符<=是一个运算符并对其进行特殊处理；例如，它知道这i<5是一个表达式而不是变量名。将操作符识别为操作符与决定操作符实际做什么是一个独立的过程，并且更紧密地集成到编译器中 - 这就是为什么您可以自定义后者而不是前者。
For languages which have an open-source compiler (such as GCC) you could, theoretically, modify the compiler to recognize a new operator. But it wouldn't be particularly easy, and besides, everyone would need your custom compiler to use your code.
对于具有开源编译器（例如 GCC）的语言，理论上您可以修改编译器以识别新的运算符。但这不会特别容易，此外，每个人都需要您的自定义编译器来使用您的代码。
回答by Paul Hooper
Not only can you not do that, but why would you want to?
你不仅不能这样做，而且你为什么要这样做？
I'm not sure what type your y and z are, but if they are of a numeric value type, you could probably use:
我不确定你的 y 和 z 是什么类型，但如果它们是数值类型，你可能会使用：
var x = Math.Min(y, z);
Though personally, I would still prefer:
虽然就个人而言，我仍然更喜欢：
var x = (y < z) ? y : z;
But I'm a bit of a ? : junky.
但我有点？: 垃圾。
Good code is not just tight and efficient, but also readable. Even if you are the only one ever reading it, you'd come back to that <?operator one day and wonder what the heck that did.
好的代码不仅要紧凑高效，还要具有可读性。即使你是唯一一个读过它的人，<?有一天你会回到那个操作员那里，想知道它到底做了什么。
回答by Rony
No, but you can create Extension Methods instead of this
不，但您可以创建扩展方法而不是这个
y.MethodName(z)
回答by Tiago Peczenyj
you can try to overload other operator like %or +to act as a <?operator.
您可以尝试重载其他运算符%或+充当<?运算符。
Will be fun
会很有趣
回答by Jeff
I'm surprised no one mentioned "order of operations".
我很惊讶没有人提到"order of operations"。
When the compiler evaluates an expression it has to be concerned with performing the operations in the correct order so that (1+2*3) = (2*3+1)multiplication always happens before addition at the same "level"in the expression.
当编译器对表达式求值时，它必须关注以正确的顺序执行运算，以便在表达式中(1+2*3) = (2*3+1)乘法总是先于加法"level"。
When you override and operator, you can change what the operator does, but not the order in which the compiler will evaluate it. If you did created a new operator, there is no way to tell the compiler what order to evaluate it in relation to the others. So if you write x <? 2 + 5Do you perform the x <? 2first then add 5 or do you perform the addition first and then do x <? 7.
当您覆盖 and 运算符时，您可以更改运算符的作用，但不能更改编译器对其求值的顺序。如果您确实创建了一个新运算符，则无法告诉编译器以什么顺序对其进行评估。因此，如果您编写x <? 2 + 5是x <? 2先执行第一个然后添加 5 还是先执行添加然后执行x <? 7.
