使用 PHP (curl) 从 JSON (Google Maps API) 中提取数据
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Using PHP (curl) to pull data from JSON (Google Maps API)
提问by Hyman W
I'm fairly new to JSON, and I'm trying to get the latitude and longitude of a geocoded city from the Google Maps API using curl. The function I'm using is:
我对 JSON 还很陌生，我正在尝试使用 curl 从 Google Maps API 获取地理编码城市的纬度和经度。我正在使用的功能是：
function geocode($city){
$cityclean = str_replace (" ", "+", $city);
$details_url = "http://maps.googleapis.com/maps/api/geocode/json?address=" . $cityclean . "&sensor=false";
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $details_url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$geoloc = json_decode(curl_exec($ch), true);
$step1 = $geoloc['results'];
$step2 = $step1['geometry'];
$coords = $step2['location'];
print $coords['lat'];
print $coords['lng'];
}
The goal of all of that is to pull the lat and lng values from the Results -> Geometry -> Location array of the following JSON:
所有这些的目标是从以下 JSON 的 Results -> Geometry -> Location 数组中提取 lat 和 lng 值：
{
"status": "OK",
"results": [ {
"types": [ "locality", "political" ],
"formatted_address": "Westminster, London, UK",
"address_components": [ {
"long_name": "London",
"short_name": "London",
"types": [ "locality", "political" ]
}, {
"long_name": "Westminster",
"short_name": "Westminster",
"types": [ "administrative_area_level_3", "political" ]
}, {
"long_name": "Greater London",
"short_name": "Greater London",
"types": [ "administrative_area_level_2", "political" ]
}, {
"long_name": "England",
"short_name": "England",
"types": [ "administrative_area_level_1", "political" ]
}, {
"long_name": "United Kingdom",
"short_name": "GB",
"types": [ "country", "political" ]
} ],
"geometry": {
"location": {
"lat": 51.5001524,
"lng": -0.1262362
},
"location_type": "APPROXIMATE",
"viewport": {
"southwest": {
"lat": 51.3493528,
"lng": -0.3783580
},
"northeast": {
"lat": 51.7040647,
"lng": 0.1502295
}
},
"bounds": {
"southwest": {
"lat": 51.3493528,
"lng": -0.3783580
},
"northeast": {
"lat": 51.7040647,
"lng": 0.1502295
}
}
}
} ]
}
However, it doesn't print anything. I know that the function successfully retrieves the JSON from Google and brings it to my server, as I did a print statement for the 'status' value and it returned 'OK'. The problem seems to be when I try and delve deeper into the JSON.
但是，它不打印任何内容。我知道该函数成功地从 Google 检索了 JSON 并将其传送到我的服务器，因为我为 'status' 值做了一个打印语句，它返回了 'OK'。问题似乎出在我尝试深入研究 JSON 时。
Sorry if it's a straightforward problem, but like I said, I'm new to this and it's driving me crazy now.
对不起，如果这是一个简单的问题，但就像我说的，我是新手，现在让我发疯了。
Thanks a lot! :)
非常感谢！:)
采纳答案by Pascal MARTIN
Note that it seems that resultscontains an array(with only one item in it, here)of results ; and geometryis one item inside one result.
请注意，它似乎results包含一个结果数组（此处只有一项）；并且geometry是一个结果中的一项。
Here, you can see that results' content is delimited by []-- which indicates it's an array.
在这里，您可以看到结果的内容由[]--分隔，表示它是一个数组。
So, you have to first access the first result : $geoloc['results'][0]
Inside of which you'll have the geometry : $geoloc['results'][0]['geometry']
因此，您必须首先访问第一个结果：$geoloc['results'][0]
在其中您将拥有几何图形：$geoloc['results'][0]['geometry']
Which will allow you to get the latitude and longitude :
这将允许您获得纬度和经度：
var_dump($geoloc['results'][0]['geometry']['location']['lat']);
var_dump($geoloc['results'][0]['geometry']['location']['lng']);
I suppose that, depending on the address you've searched on, you will sometimes have more than one item in the resultsarray.
我想，根据您搜索的地址，您有时会在results数组中拥有多个项目。
回答by Fernando Cardenas 'Pelonxz'
You just need this :
你只需要这个：
$fullurl = "http://maps.googleapis.com/maps/api/geocode/json?address=1600+Amphitheatre+Parkway,+Mountain+View,+CA&sensor=true";
$string .= file_get_contents($fullurl); // get json content
$json_a = json_decode($string, true); //json decoder
echo $json_a['results'][0]['geometry']['location']['lat']; // get lat for json
echo $json_a['results'][0]['geometry']['location']['lng']; // get ing for json
