php 如何遍历php中的对象
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/8664208/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
提示：将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间：2020-08-26 05:12:45 来源:igfitidea点击:
How to loop through objects in php
提问by mcbeav
I am not too familiar with objects, i usually convert them to arrays using a script, but i thought it was time to man up and learn this, so i am asking how can i loop through an array of objects and pull out the specific information i need, the example of what is being returned is below.
我对对象不太熟悉，我通常使用脚本将它们转换为数组，但我认为是时候开始学习了，所以我问我如何遍历对象数组并提取特定信息我需要，返回内容的示例如下。
[2] => stdClass Object
(
[id_str] => 152240682071900161
[in_reply_to_status_id] =>
[contributors] =>
[place] =>
[truncated] =>
[geo] =>
[favorited] =>
[created_at] => Thu Dec 29 04:13:01 +0000 2011
[user] => stdClass Object
(
[id_str] => 71876190
[contributors_enabled] =>
[lang] => en
[protected] =>
[url] => http://www.imdb.com/name/nm0000362/
[default_profile] => 1
[profile_use_background_image] => 1
[name] => Danny DeVito
[default_profile_image] =>
[friends_count] => 14
[profile_text_color] => 333333
[statuses_count] => 5361
[profile_background_image_url] => http://a0.twimg.com/images/themes/theme1/bg.png
[utc_offset] => -28800
[description] => I'm an actor, director and producer.
[is_translator] =>
[created_at] => Sat Sep 05 19:44:48 +0000 2009
[profile_link_color] => 0084B4
[following] => 1
[profile_background_image_url_https] => https://si0.twimg.com/images/themes/theme1/bg.png
[favourites_count] => 8
[follow_request_sent] =>
[geo_enabled] => 1
[profile_background_color] => C0DEED
[profile_background_tile] =>
[followers_count] => 1784732
[profile_image_url] => http://a2.twimg.com/profile_images/400232403/Photo_6_normal.jpg
[screen_name] => DannyDeVito
[show_all_inline_media] =>
[profile_sidebar_fill_color] => DDEEF6
[profile_image_url_https] => https://si0.twimg.com/profile_images/400232403/Photo_6_normal.jpg
[listed_count] => 20918
[notifications] =>
[location] => Los Angeles
[id] => 71876190
[verified] => 1
[time_zone] => Pacific Time (US & Canada)
[profile_sidebar_border_color] => C0DEED
)
[in_reply_to_user_id] =>
[retweet_count] => 10
[in_reply_to_screen_name] =>
[in_reply_to_status_id_str] =>
[possibly_sensitive] =>
[retweeted] =>
[source] => WhoSay
[in_reply_to_user_id_str] =>
[coordinates] =>
[id] => 1.52240682072E+17
[text] => #Trollfoot Maroma http://t.co/4MvCYIFe
)
[3] => stdClass Object
(
[id_str] => 152240419344879616
[in_reply_to_status_id] =>
[contributors] =>
[place] =>
[truncated] =>
[geo] =>
[favorited] =>
[created_at] => Thu Dec 29 04:11:59 +0000 2011
[user] => stdClass Object
(
[id_str] => 71876190
[default_profile] => 1
[contributors_enabled] =>
[lang] => en
[protected] =>
[url] => http://www.imdb.com/name/nm0000362/
[profile_use_background_image] => 1
[name] => Danny DeVito
[default_profile_image] =>
[friends_count] => 14
[profile_text_color] => 333333
[statuses_count] => 5361
[profile_background_image_url] => http://a0.twimg.com/images/themes/theme1/bg.png
[utc_offset] => -28800
[description] => I'm an actor, director and producer.
[is_translator] =>
[created_at] => Sat Sep 05 19:44:48 +0000 2009
[profile_link_color] => 0084B4
[following] => 1
[profile_background_image_url_https] => https://si0.twimg.com/images/themes/theme1/bg.png
[favourites_count] => 8
[follow_request_sent] =>
[geo_enabled] => 1
[profile_background_color] => C0DEED
[profile_background_tile] =>
[followers_count] => 1784725
[profile_image_url] => http://a2.twimg.com/profile_images/400232403/Photo_6_normal.jpg
[screen_name] => DannyDeVito
[show_all_inline_media] =>
[profile_sidebar_fill_color] => DDEEF6
[profile_image_url_https] => https://si0.twimg.com/profile_images/400232403/Photo_6_normal.jpg
[listed_count] => 20918
[notifications] =>
[location] => Los Angeles
[id] => 71876190
[verified] => 1
[time_zone] => Pacific Time (US & Canada)
[profile_sidebar_border_color] => C0DEED
)
[in_reply_to_user_id] =>
[retweet_count] => 15
[in_reply_to_screen_name] =>
[in_reply_to_status_id_str] =>
[possibly_sensitive] =>
[retweeted] =>
[source] => WhoSay
[in_reply_to_user_id_str] =>
[coordinates] =>
[id] => 1.52240419345E+17
[text] => #Trolltoll Maroma http://t.co/Egv9syon
)
回答by DarthVader
you dont need to convert them to anything.
你不需要将它们转换成任何东西。
foreach loop would work fine with you as follows in generic:
foreach 循环可以正常工作，如下一般：
foreach ($objects as $obj) {
echo $obj->property;
}
for a inner object this would work:
对于内部对象，这将起作用：
foreach ($objects as $obj){
echo $obj->user->description;
}
