Android 如何自定义产品口味的 APK 文件名？
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How to customize the APK file name for product flavors?
提问by JJD
I am customizing the name of the APKfile of my Android application within the build.gradlescript as follows:
我正在脚本中自定义我的 Android 应用程序的 APK文件的名称，build.gradle如下所示：
android {
defaultConfig {
project.ext.set("archivesBaseName", "MyApplication");
}
}
Now that I am using product flavors:
现在我正在使用产品口味：
android {
productFlavors {
green {
applicationId "com.example.myapplication.green"
}
blue {
applicationId "com.example.myapplication.blue"
}
}
}
Is there a way to customize the name of each APK? I experimented with archiveBaseNameand baseNamewithout success. In the end I want to come up with the following files:
有没有办法自定义每个 APK的名称？我尝试过，archiveBaseName也baseName没有成功。最后我想提出以下文件：
build/outputs/apk/Blue-debug-1.2.1.apk
build/outputs/apk/Blue-debug-unaligned.apk
build/outputs/apk/Blue-release-1.2.1.apk
build/outputs/apk/Blue-release-unaligned.apk
build/outputs/apk/Green-debug-1.2.1.apk
build/outputs/apk/Green-debug-unaligned.apk
build/outputs/apk/Green-release-1.2.1.apk
build/outputs/apk/Green-release-unaligned.apk
回答by Lakshman Chilukuri
Try to put this in your android closure of build.gradle
尝试将其放在 build.gradle 的 android 闭包中
buildTypes {
debug {
// debug buildType specific stuff
}
release {
// release buildType specific stuff
}
applicationVariants.all { variant ->
if (variant.buildType.name.equals("release") &&
variant.productFlavors[0].name.equals("green") &&
variant.zipAlign) {
def apk = variant.outputFile;
variant.outputFile = new File(apk.parentFile, "green.apk");
} else if(variant.buildType.name.equals("release") &&
variant.productFlavors[0].name.equals("blue") &&
variant.zipAlign) {
def apk = variant.outputFile;
variant.outputFile = new File(apk.parentFile, "blue.apk");
}
}
}
Now the outputs should be like green.apkand blue.apk.
现在输出应该像green.apk和blue.apk。
回答by notz
For Android Gradle Plugin 0.13.+ you should use something like this:
对于 Android Gradle Plugin 0.13.+ 你应该使用这样的东西：
android{
buildTypes {
applicationVariants.all { variant ->
variant.outputs.each { output ->
def apk = output.outputFile;
def newName = "mysms-" + variant.baseName.replace("-release", "") + "-" + defaultConfig.versionName + ".apk";
output.outputFile = new File(apk.parentFile, newName);
}
}
}
}
回答by Joao Cesar Stange
For Android Studio 3.0 you must change from:
对于 Android Studio 3.0，您必须从：
applicationVariants.all { variant ->
variant.outputs.each { output ->
output.outputFile = new File(output.outputFile.parent, "whatever" + ".apk")
}
}
To:
到：
android.applicationVariants.all { variant ->
variant.outputs.all {
outputFileName = "whatever" + ".apk")
}
}
回答by user1252459
I did it like this:
我是这样做的：
productFlavors {
production {
applicationId "com.example.production"
}
staging {
applicationId "com.example.production.staging"
}
applicationVariants.all { variant ->
variant.outputs.each { output ->
if(variant.productFlavors[0].name.equals("staging")){
output.outputFile = new File(output.outputFile.parent,
output.outputFile.name.replace("app-staging-release", "test"));
}else{
output.outputFile = new File(output.outputFile.parent,
output.outputFile.name.replace("app-production-release", "production"));
}
}
}
}
回答by Jelle
It's weird that you would need this because the apk filename is already differentby default.
你需要这个很奇怪，因为默认情况下apk 文件名已经不同了。
If you look hereat line 1346, you can see that the variantData.variantConfiguration.baseName is used in the outputFile.
如果您在此处查看第 1346 行，您可以看到在 outputFile 中使用了 variantData.variantConfiguration.baseName。
variantData.outputFile = project.file("$project.buildDir/apk/${project.archivesBaseName}-${variantData.variantConfiguration.baseName}.apk")
And the documentation for baseNameis
和文档baseName是
/**
* Full, unique name of the variant, including BuildType, flavors and test, dash separated.
* (similar to full name but with dashes)
*/
private String mBaseName;
So running gradle assembleFreeDebugshould get you a ProjectName-free-debug.apkfile.
所以运行gradle assembleFreeDebug应该会给你一个ProjectName-free-debug.apk文件。
But if that isn't the case, or you want a different filename, you can use the following code to customize it.
但如果情况并非如此，或者您想要不同的文件名，则可以使用以下代码对其进行自定义。
android {
buildTypes {
debug {}
alpha {}
release {}
}
productFlavors {
free{}
paid{}
}
applicationVariants.all { variant ->
def newApkName = variant.name + "my-custom-addition" + ".apk";
variant.outputFile = new File("${project.buildDir}/outputs/apk/", newApkName);
}
}
回答by Happy Singh
This will help you in 2020.
这将在 2020 年为您提供帮助。
android {
//........
flavorDimensions "version"
productFlavors {
Free {
dimension "version"
applicationId "com.exampleFree.app"
}
Paid {
dimension "version"
applicationId "com.examplePaid.app"
}
}
applicationVariants.all { variant ->
variant.outputs.all { output ->
def appId = variant.applicationId// com.exampleFree.app OR com.examplePaid.app
def versionName = variant.versionName
def versionCode = variant.versionCode // e.g 1.0
def flavorName = variant.flavorName // e. g. Free
def buildType = variant.buildType.name // e. g. debug
def variantName = variant.name // e. g. FreeDebug
//customize your app name by using variables
outputFileName = "${variantName}.apk"
}
}}
Apk name FreeDebug.apk
Apk 名称FreeDebug.apk
Proof
证明
回答by Daniel Wilson
Every answer here is the same, and outdated. It's easy to do [flavor]-[version]-[build type]:
这里的每个答案都是一样的，而且已经过时了。很容易做到[风味]-[版本]-[构建类型]：
android {
productFlavors {
green {
applicationId "com.example.myapplication.green"
setProperty("archivesBaseName", "Green-" + defaultConfig.versionName)
}
blue {
applicationId "com.example.myapplication.blue"
setProperty("archivesBaseName", "Blue-" + defaultConfig.versionName)
}
}
}
If your versionName is "1.2.1", running gradle assemble will produce:
如果您的 versionName 是“1.2.1”，运行 gradle assemble 将产生：
Green-1.2.1-debug.apk
Green-1.2.1-debug.apk
Green-1.2.1-release.apk
Green-1.2.1-release.apk
Blue-1.2.1-debug-apk
Blue-1.2.1-debug-apk
Blue-1.2.1-release.apk
Blue-1.2.1-release.apk
回答by Trinea
This is what you need
这就是你需要的
android {
defaultConfig {
……
// custom output apk name
applicationVariants.all { variant ->
variant.outputs.all {
outputFileName = "${variant.productFlavors[0].name}-${variant.buildType.name}-${variant.versionName}.apk"
}
}
}
……
}
回答by Rui Correia
This work for me:
这对我有用：
Add the variant.productFlavors[0].namein the APK name.
variant.productFlavors[0].name在 APK 名称中添加。
Code example:
代码示例：
buildTypes {
release {
minifyEnabled false
proguardFiles getDefaultProguardFile('proguard-android.txt'), 'proguard-rules.pro'
applicationVariants.all { variant ->
variant.outputs.each { output ->
output.outputFile = new File(output.outputFile.parent, "APPNAME_" + variant.productFlavors[0].name + "_" + variant.versionName + ".apk")
}
}
}
}
回答by William T. Mallard
Here's my variant (heh) of Lakshman's answer above, not sure why I needed the "variants.outputs.each" but I did.
这是我上面 Lakshman 答案的变体（heh），不知道为什么我需要“variants.outputs.each”，但我做到了。
defaultConfig {
applicationId "my.company.com"
minSdkVersion 16
targetSdkVersion 25
applicationVariants.all { variant ->
if (variant.productFlavors[0].name.equals("VariantA")) {
variant.outputs.each { output ->
def apk = output.outputFile;
output.outputFile = new File(apk.parentFile, "Blue.apk");
}
} else { // Only two variants
variant.outputs.each { output ->
def apk = output.outputFile;
output.outputFile = new File(apk.parentFile, "Green.apk");
}
}
}
}
