C++ 如何从 LPWSTR 转换为 'const char*'
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how to convert from LPWSTR to 'const char*'
提问by olidev
After getting a struct from C# to C++ using C++/CLI:
使用 C++/CLI 将结构从 C# 获取到 C++ 后：
public value struct SampleObject
{
LPWSTR a;
};
I want to print its instance:
我想打印它的实例：
printf(sampleObject->a);
but I got this error:
但我收到了这个错误：
Error 1 error C2664: 'printf' : cannot convert parameter 1 from 'LPWSTR' to 'const char *'
错误 1 错误 C2664：“printf”：无法将参数 1 从“LPWSTR”转换为“const char *”
How can I convert from LPWSTR to char*?
我怎样才能从 转换LPWSTR to char*？
Thanks in advance.
提前致谢。
采纳答案by Nawaz
Don't convert.
不要转换。
Use wprintfinstead of printf:
使用wprintf代替printf：
See the exampleswhich explains how to use it.
请参阅说明如何使用它的示例。
Alternatively, you can use std::wcoutas:
或者，您可以std::wcout用作：
wchar_t *wstr1= L"string";
LPWSTR wstr2= L"string"; //same as above
std::wcout << wstr1 << L", " << wstr2;
Similarly, use functions which are designed for wide-char, and forget the idea of converting wchar_tto char, as it may loss data.
同样，使用为宽字符设计的函数，忘记转换wchar_t为的想法char，因为它可能会丢失数据。
Have a look at the functions which deal with wide-char here:
在这里查看处理宽字符的函数：
回答by Ivan Gozali
Use the wcstombs()function, which is located in <stdlib.h>. Here's how to use it:
使用wcstombs()位于 中的函数<stdlib.h>。以下是如何使用它：
LPWSTR wideStr = L"Some message";
char buffer[500];
// First arg is the pointer to destination char, second arg is
// the pointer to source wchar_t, last arg is the size of char buffer
wcstombs(buffer, wideStr, 500);
printf("%s", buffer);
Hope this helped someone! This function saved me from a lot of frustration.
希望这对某人有所帮助！这个功能让我免于很多挫折。
回答by MSalters
Just use printf("%ls", sampleObject->a). The use of lin %lsmeans that you can pass a wchar_t[]such as L"Wide String".
只需使用printf("%ls", sampleObject->a). lin的使用%ls意味着您可以传递wchar_t[]诸如L"Wide String".
(No, I don't know why the L and w prefixes are mixed all the time)
（不，我不知道为什么 L 和 w 前缀总是混合在一起）
回答by 79E09796
int length = WideCharToMultiByte(cp, 0, sampleObject->a, -1, 0, 0, NULL, NULL);
char* output = new char[length];
WideCharToMultiByte(cp, 0, sampleObject->a, -1, output , length, NULL, NULL);
printf(output);
delete[] output;
回答by Lakshmanan Meiyappan
回答by HaSeeB MiR
use WideCharToMultiByte()method to convert multi-byte character.
使用WideCharToMultiByte()方法来转换多字节字符。
Here is example of converting from LPWSTR to char* or wide character to character.
这是从 LPWSTR 转换为 char* 或从宽字符转换为字符的示例。
/*LPWSTR to char* example.c */
#include <stdio.h>
#include <windows.h>
void LPWSTR_2_CHAR(LPWSTR,LPSTR,size_t);
int main(void)
{
wchar_t w_char_str[] = {L"This is wide character string test!"};
size_t w_len = wcslen(w_char_str);
char char_str[w_len + 1];
memset(char_str,'##代码##',w_len * sizeof(char));
LPWSTR_2_CHAR(w_char_str,char_str,w_len);
puts(char_str);
return 0;
}
void LPWSTR_2_CHAR(LPWSTR in_char,LPSTR out_char,size_t str_len)
{
WideCharToMultiByte(CP_ACP,WC_COMPOSITECHECK,in_char,-1,out_char,str_len,NULL,NULL);
}
