php 合并日期和时间
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Merge Date & Time
提问by CodeGuru
$combinedDT = date('Y-m-d H:i:s', strtotime('$date $time'));
Date Format 2013-10-14
日期格式 2013-10-14
time format 23:40:19
时间格式 23:40:19
i'm getting zeros when trying to store into a datetime datatype
尝试存储到日期时间数据类型时我得到零
回答by Amal Murali
You're currently doing strtotime('$date $time'). Variables wrapped in single-quotes aren't interpolated. If you use single-quotes, PHP will treat it as a literal string, and strototime()will try to convert the string $date $timeinto a timestamp.
你目前正在做strtotime('$date $time'). 用单引号括起来的变量没有内插。如果使用单引号，PHP 会将其视为文字字符串，并strototime()尝试将字符串$date $time转换为时间戳。
It'll fail and that would explain why you're getting incorrect results.
它会失败，这将解释为什么你得到不正确的结果。
You need to use double quotes instead:
您需要改用双引号：
$combinedDT = date('Y-m-d H:i:s', strtotime("$date $time"));
^ ^
回答by Wilbo Baggins
And for those coming here working with DateTime objects:
对于那些来这里使用 DateTime 对象的人：
$date = new DateTime('2017-03-14');
$time = new DateTime('13:37:42');
// Solution 1, merge objects to new object:
$merge = new DateTime($date->format('Y-m-d') .' ' .$time->format('H:i:s'));
echo $merge->format('Y-m-d H:i:s'); // Outputs '2017-03-14 13:37:42'
// Solution 2, update date object with time object:
$date->setTime($time->format('H'), $time->format('i'), $time->format('s'));
echo $date->format('Y-m-d H:i:s'); // Outputs '2017-03-14 13:37:42'
