Python 将 12 小时转换为 24 小时时间

Convert 12 hour into 24 hour times

提问by Ryflex

I'm trying to convert times from 12 hour times into 24 hour times...

我正在尝试将时间从 12 小时制转换为 24 小时制...

Automatic Example times:

自动示例时间：

06:35  ## Morning
11:35  ## Morning (If m2 is anywhere between 10:00 and 12:00 (morning to mid-day) during the times of 10:00 and 13:00 (1pm) then the m2 time is a morning time)
1:35  ## Afternoon
11:35  ## Afternoon

Example code:

示例代码：

m2 = "1:35" ## This is in the afternoon.
m2 = datetime.strptime(m2, "%H:%M")
print m2

Expected Output:

预期输出：

13:35

Actual Output:

实际输出：

1900-01-01 01:35:00

---

---

I tried a second variation but again didn't help :/

我尝试了第二个变体，但再次没有帮助：/

m2 = "1:35" ## This is in the afternoon.
m2split = m2.split(":")
if len(m2split[0]) == 1:
    m2 = ("""%s%s%s%s""" % ("0", m2split[0], ":", m2split[1]))
    print m2
m2temp = datetime.strptime(m2, "%I:%M")
m2 = m2temp.strftime("%H:%M")

---

---

What am I doing wrong and how can I fix this?

我做错了什么，我该如何解决？

采纳答案by SMNALLY

Try this :)

尝试这个 ：）

Code:

代码：

currenttime = datetime.datetime.now().time().strftime("%H:%M")
if currenttime >= "10:00" and currenttime <= "13:00":
    if m2 >= "10:00" and m2 >= "12:00":
        m2 = ("""%s%s""" % (m2, " AM"))
    else:
        m2 = ("""%s%s""" % (m2, " PM"))
else:
    m2 = ("""%s%s""" % (m2, " PM"))
m2 = datetime.datetime.strptime(m2, '%I:%M %p')
m2 = m2.strftime("%H:%M %p")
m2 = m2[:-3]
print m2

Output:

输出：

13:35

回答by dan04

You need to specify that you mean PM instead of AM.

您需要指定您的意思是 PM 而不是 AM。

>>> from datetime import *
>>> m2 = '1:35 PM'
>>> m2 = datetime.strptime(m2, '%I:%M %p')
>>> print(m2)
1900-01-01 13:35:00

回答by modpy

This approach uses strptime and strftime with format directives as per https://docs.python.org/2/library/datetime.html#strftime-strptime-behavior, %H is the 24 hour clock, %I is the 12 hour clock and when using the 12 hour clock, %p qualifies if it is AM or PM.

这种方法根据https://docs.python.org/2/library/datetime.html#strftime-strptime-behavior使用 strptime 和 strftime 和格式指令，%H 是 24 小时制，%I 是 12 小时制当使用 12 小时制时，%p 限定是 AM 还是 PM。

    >>> from datetime import datetime
    >>> m2 = '1:35 PM'
    >>> in_time = datetime.strptime(m2, "%I:%M %p")
    >>> out_time = datetime.strftime(in_time, "%H:%M")
    >>> print(out_time)
    13:35

回答by NagMani

time = raw_input().strip() # input format in hh:mm:ssAM/PM
t_splt = time.split(':')
if t_splt[2][2:] == 'PM' and t_splt[0] != '12':
    t_splt[0] = str(12+ int(t_splt[0]))
elif int(t_splt[0])==12 and t_splt[2][2:] == 'AM':
    t_splt[0] = '00'
t_splt[2] = t_splt[2][:2]
print ':'.join(t_splt)

回答by Alessandro

Try this

尝试这个

dicti = 
{'01':13,'02':14,'03':15,'04':16,'05':17,'06':18,'07':19,'08':20,'09':21,'10':22,'11':23,'12':12}
s = '12:40:22PM'
if s.endswith('AM'):
if s.startswith('12'):
    s1=s[:8]
    bb=s1.replace('12','00')
    print bb
else:
    s1=s[:8]
    print s1
else:
s1=s[:8]
time= str(s[:2])
ora=str(dicti[time])
aa=s1.replace(time,ora)
print aa

回答by Vikas P

If date is in this format (HH:MM:SSPM/AM) the following code is effective :

如果日期采用这种格式 (HH:MM:SSPM/AM)，则以下代码有效：

a=''
def timeConversion(s):
   if s[-2:] == "AM" :
      if s[:2] == '12':
          a = str('00' + s[2:8])
      else:
          a = s[:-2]
   else:
      if s[:2] == '12':
          a = s[:-2]
      else:
          a = str(int(s[:2]) + 12) + s[2:8]
   return a


s = '11:05:45AM'
result = timeConversion(s)
print(result)

回答by szerem

%HHour (24-hour clock) as a zero-padded decimal number.
%IHour (12-hour clock) as a zero-padded decimal number.

%H小时（24 小时制）作为补零的十进制数。
%I小时（12 小时制）作为用零填充的十进制数。

m2 = "1:35" ## This is in the afternoon.
m2 = datetime.strptime(m2, "<b>%I</b>:%M")
print(m2)

回答by Alok Kumar Singh

One more way to do this cleanly

另一种干净利落的方法

def format_to_24hr(twelve_hour_time): return datetime.strftime( datetime.strptime( twelve_hour_time, '%Y-%m-%d %I:%M:%S %p' ), "%Y-%m-%d %H:%M:%S")

def format_to_24hr(twelve_hour_time): return datetime.strftime( datetime.strptime( twelve_hour_time, '%Y-%m-%d %I:%M:%S %p' ), "%Y-%m-%d %H:%M:%S")

回答by Oldemiro Henry Williams Baloi

Instead of using "H" for hour indication use "I" as described in the example bellow:

使用“I”代替“H”作为小时指示使用“I”，如以下示例中所述：

from datetime import *
m2 = 'Dec 14 2018 1:07PM'
m2 = datetime.strptime(m2, '%b %d %Y %I:%M%p')
print(m2)

Please check this link

请检查此链接