bash Shell 脚本在延迟后生成一个进程
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/1915062/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Shell script spawning a process after a delay
提问by gerdemb
How can I spawn a process after a delay in a shell script? I want a command to start 60 seconds after the script starts, but I want to keep running the rest of the script without waiting 60 seconds first. Here's the idea:
如何在 shell 脚本延迟后生成进程？我想要一个命令在脚本启动 60 秒后启动，但我想继续运行脚本的其余部分而不先等待 60 秒。这是想法：
#!/bin/sh
# Echo A 60 seconds later, but without blocking the rest of the script
sleep 60 && echo "A"
echo "B"
echo "C"
The output should be
输出应该是
B
C
... 60 seconds later
A
I need to be able to do this all in one script. Ie. no creating a second script that is called from the first shell script.
我需要能够在一个脚本中完成这一切。IE。没有创建从第一个 shell 脚本调用的第二个脚本。
回答by nos
& starts a background job, so
& 开始后台工作，所以
sleep 60 && echo "A" &
回答by davrieb
A slight expansion on the other answers is to wait for the backgrounded commands at the end of the script.
其他答案的轻微扩展是等待脚本末尾的后台命令。
#!/bin/sh
# Echo A 60 seconds later, but without blocking the rest of the script
set -e
sleep 60 && echo "A" &
pid=$!
echo "B"
echo "C"
wait $pid
回答by lorenzog
Can't try it right now but
现在不能尝试，但是
(sleep 60 && echo "A")&
(sleep 60 && echo "A")&
should do the job
应该做这份工作
回答by Jeroen Vermeulen - MageHost
Alternative:
选择：
echo 'echo "A"' | at now + 1 min
If somehow the OS is not running at the specified time, the command will be executed as soon as it is available.
如果操作系统未在指定时间运行，则该命令将在可用时立即执行。
