C++ std::cout 打印字符 N 次
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std::cout to print character N times
提问by shiraz
How can I print a character N number of times using std::coutwithout looping?
如何在std::cout不循环的情况下使用 N 次打印字符？
Is there a way to move the text cursor back to nullify the effect of std::cout << std::endl;? i.e. to move up a line (say we never printed anything after doing the std::cout << std::endl;operation).
有没有办法将文本光标移回以抵消 的效果std::cout << std::endl;？即向上移动一行（假设我们在执行std::cout << std::endl;操作后从未打印任何内容）。
回答by sehe
std::cout << std::string(100, '*') << std::endl;
To move a line up, you have to resort to terminal escapes (assuming that isatty()indicates that you are running on one).
要向上移动一行，您必须求助于终端转义（假设这isatty()表明您正在运行一个）。
回答by Benjamin Lindley
std::cout << std::setfill(the_char) << std::setw(100) << "";
回答by Mawg says reinstate Monica
is there a way to back our way to nullify the effect of cout << endl; i.e. to move up a line(say we never printed anything after doing the cout << endl; operation) Thank you so much!
有没有办法支持我们的方法来使 cout << endl 的效果无效；即向上移动一行（假设我们在执行 cout << endl; 操作后从未打印任何内容）非常感谢！
Use the ternary operator(or an if statement if you refer) ... something like ...
使用三元运算符（或 if 语句，如果你指的是）......类似......
void PrintCharNtimes(char chatToPrint; int numTimes)
{
std::cout << std::string(numTimes, chatToPrint) << (numTimes > 0) ? std::endl : ;
}
