我想在我的代码中有一个是/否循环，但我在这样做时遇到了麻烦（python 3.3）
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I want to have a yes/no loop in my code, but I'm having trouble doing it (python 3.3)
提问by user3412375
Sorry I'm just a beginner at python so this is probably a very simple question, but I have a code and I want to loop it so after the code asks the user if they want to play again and the user inputs 'yes' to restart the code and 'no' to end the code. If they input anything other than yes or no it should ask tell them to enter yes or no then ask the question again. How would I do this exactly? (I do know about while and for loops but I'm not sure how I would use them in this way)
抱歉，我只是 python 的初学者，所以这可能是一个非常简单的问题，但是我有一个代码，我想循环它，以便在代码询问用户是否要再次播放并且用户输入“是”之后重新启动代码并“否”结束代码。如果他们输入的是或否以外的任何内容，它应该要求告诉他们输入是或否，然后再次提问。我将如何做到这一点？（我确实知道 while 和 for 循环，但我不确定如何以这种方式使用它们）
回答by Aswin Murugesh
This is a simple one:
这是一个简单的：
while True:
a = input("Enter yes/no to continue")
if a=="yes":
gameplay()
continue
elif a=="no":
break
else:
print("Enter either yes/no")
Where gameplay function contains the code to be executed
其中gameplay函数包含要执行的代码
回答by halex
I would do it the following way:
我会这样做：
while True:
# your code
cont = raw_input("Another one? yes/no > ")
while cont.lower() not in ("yes","no"):
cont = raw_input("Another one? yes/no > ")
if cont == "no":
break
If you use Python3 change raw_inputto input.
如果您使用 Python3，请更改raw_input为input.
回答by Signus
My approach to this:
我的方法是：
# Sets to simplify if/else in determining correct answers.
yesChoice = ['yes', 'y']
noChoice = ['no', 'n']
# Prompt the user with a message and get their input.
# Convert their input to lowercase.
input = raw_input("Would you like to play again? (y/N) ").lower()
# Check if our answer is in one of two sets.
if input in yesChoice:
# call method
elif input in noChoice:
# exit game
exit 0
else:
print "Invalid input.\nExiting."
exit 1
回答by user3330510
I think this is what you are looking for
我想这就是你要找的
def playGame():
# your code to play
if __name__ == '__main__':
play_again = 'start_string'
while not play_again in ['yes', 'no']:
play_again = raw_input('Play Again? (type yes or no) ')
if play_again == 'yes':
playGame()
回答by Juan Martinez
I tried this short boolean script that will maintain the loop until the if statement is satisfied:
我尝试了这个简短的布尔脚本，它将保持循环直到满足 if 语句：
something = False
while not something:
inout = raw_input('type "Hello" to break the loop: ')
if inout == 'Hello':
something = True
