python中十六进制字符串变量到十六进制值的转换
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Hex string variable to hex value conversion in python
提问by drdot
I have a variable call hex_string. The value could be '01234567'. Now I would like to get a hex value from this variable which is 0x01234567 instead of string type. The value of this variable may change. So I need a generic conversion method.
我有一个变量调用 hex_string。该值可能是“01234567”。现在我想从这个变量中获取一个十六进制值，它是 0x01234567 而不是字符串类型。这个变量的值可能会改变。所以我需要一个通用的转换方法。
采纳答案by Jonathon Reinhart
I think you might be mixing up numbers and their representations. 0x01234567and 19088743are the exact same thing. "0x01234567"and "19088743"are not (note the quotes).
我认为您可能混淆了数字及其表示。0x01234567并且19088743是完全一样的东西。"0x01234567"并且"19088743"不是（注意引号）。
To go from a string of hexadecimal characters, to an integer, use int(value, 16).
要将十六进制字符串转换为整数，请使用int(value, 16).
To go from an integer, to a string that represents that number in hex, use hex(value).
要将整数转换为以十六进制表示该数字的字符串，请使用hex(value).
>>> a = 0x01234567
>>> b = 19088743
>>> a == b
True
>>> hex(b)
'0x1234567'
>>> int('01234567', 16)
19088743
>>>
回答by jamylak
>>> int('01234567', 16)
19088743
This is the same as:
这与：
>>> 0x01234567
19088743
回答by rajpy
>>> a
'01234567'
>>> hex(int(a))
'0x12d687'
>>>
Hope it helps..
希望能帮助到你..
回答by onaclov2000
I don't know the proper 'pythonic' way to do this but here was what I came up with.
我不知道正确的“pythonic”方式来做到这一点，但这是我想出的。
def hex_string_to_bin_string(input):
lookup = {"0" : "0000", "1" : "0001", "2" : "0010", "3" : "0011", "4" : "0100", "5" : "0101", "6" : "0110", "7" : "0111", "8" : "1000", "9" : "1001", "A" : "1010", "B" : "1011", "C" : "1100", "D" : "1101", "E" : "1110", "F" : "1111"}
result = ""
for byte in input:
result = result + lookup[byte]
return result
def hex_string_to_hex_value(input):
value = hex_string_to_bin_string(input)
highest_order = len(value) - 1
result = 0
for bit in value:
result = result + int(bit) * pow(2,highest_order)
highest_order = highest_order - 1
return hex(result)
print hex_string_to_hex_value("FF")
The result being
结果是
0xff
Also trying print hex_string_to_hex_value("01234567")
还尝试打印 hex_string_to_hex_value("01234567")
results in
结果是
0x1234567L
Note: the L indicates the value falls into category of a "long" as far as I can tell based on the documentation from the python website (they do show that you can have a L value appended). https://docs.python.org/2/library/functions.html#hex
注意：根据 python 网站上的文档，L 表示该值属于“长”类别（它们确实表明您可以附加 L 值）。 https://docs.python.org/2/library/functions.html#hex
>>> hex(255)
'0xff'
>>> hex(-42)
'-0x2a'
>>> hex(1L)
'0x1L'
回答by Tarun Yadav
hex value is <type 'long'>while hex string is <type 'str'>. All operations on hex value are workable if type is changed to long from str.
十六进制值是，<type 'long'>而十六进制字符串是<type 'str'>。如果类型从 str 更改为 long，则对十六进制值的所有操作都是可行的。
long(hex_string,16)
