bash 使用循环时如何使makefile退出并出错？
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How to make makefile exit with error when using a loop?
提问by user48956
If I have the following bash command:
如果我有以下 bash 命令：
for i in ./ x ; do ls $i ; done && echo OK
"ls ./" is executed, and then "ls x", which fails (x is missing) and OK is not printed.
执行“ls ./”，然后执行“ls x”，失败（x 丢失）并且不打印 OK。
If
如果
for i in x ./ ; do ls $i ; done && echo OK
then even though "ls x" fails, because the last statement in the for loop succeeded, then OK is printed. This is a problem when using shell for loops in makefiles:
然后即使“ls x”失败，因为for循环中的最后一条语句成功，然后打印OK。在 makefile 中使用 shell for 循环时，这是一个问题：
x:
for i in $(LIST) ; do \
cmd $$i ;\
done
How can I make make fail if any of the individual executions of cmd fails?
如果 cmd 的任何单个执行失败，如何使 make 失败？
回答by Barmar
Use the breakcommand to terminate the loop when a command fails
break当命令失败时使用命令终止循环
x:
for i in $(LIST) ; do \
cmd $$i || break ;\
done
That won't make the makefile abort, though. You could instead use exitwith a non-zero code:
但是，这不会使 makefile 中止。您可以改为使用exit非零代码：
x:
for i in $(LIST) ; do \
cmd $$i || exit 1 ;\
done
回答by rashok
After executing the command, check for return value of that command using $?, as its make file you need to use double $. If its non zero, then exit with failure.
执行命令后，使用 来检查该命令的返回值$?，作为它的生成文件，您需要使用 double $。如果它非零，则退出失败。
x:
set -e
for i in $(LIST); do \
cmd $$i; \
[[ $$? != 0 ]] && exit -1; \
echo 'done'; \
done
