bash 如何在unix中比较单个文件中的两列
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how to compare two columns in a single file in unix
提问by Tejesh Chilla
My req is i need to get the output if the two columns are not equal below is my code.
我的要求是如果下面的两列不相等，我需要获取输出是我的代码。
The output is as below here my req is for example the first shouldnt be printed as both are equal the second should be printed as both are not equal.
输出如下，我的要求是例如第一个不应该打印，因为两者相等，第二个应该打印，因为两者不相等。
cat testingfull.txt|sed -n '/"Exp_CDL_BOOKINGS_F"/,/TABLEATTRIBUTE NAME/p'|grep EXPRESSION | awk -F"\"" '{print ,"=",}'
BOOK_DATE_KEY=BOOK_DATE_KEY
Lkp_BOOKINGS_FACT_KEY=iif( not isnull(i_BOOKINGS_FACT_KEY) and isnull(iif(BOOK_DATE_KEY<>Lkp_BOOK_DATE_KEY, NULL)),null,i_BOOKINGS_FACT_KEY)
BOOKINGS_FACT_KEY=Lkp_BOOKINGS_FACT_KEY
回答by anubhava
Compare columns in your awk command:
比较 awk 命令中的列：
awk -F'"' '!= {print ,"=",}'
回答by svante
This should work for you (trail this to your current line) :
这应该对您有用（将其跟踪到您当前的行）：
... | awk -F'=' '!='
