bash 将文件名分配给 shell 中的变量
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Assign file names to a variable in shell
提问by Zasito
I'm trying to write a script that does something a bit more sophisticated than what I'm going to show you, but I know that the problem is in this part.
我正在尝试编写一个脚本，它的功能比我要向您展示的要复杂一些，但我知道问题出在这一部分。
I want each name of a list of files in a directory to be assigned to a variable (the same variable, one at a time) through a forloop, then do something inside of the loop with this, see what mean:
我希望通过for循环将目录中文件列表的每个名称分配给一个变量（同一变量，一次一个），然后在循环内用这个做一些事情，看看是什么意思：
for thing in $(ls );
do
file $thing;
done
Edit: let's say this scrypt is called Scrypt and I have a folder named Folder, and it has 3 files inside named A,B,C. I want it to show me on the terminal when I write this:
编辑：假设这个 scrypt 叫做 Scrypt，我有一个名为 Folder 的文件夹，里面有 3 个文件，名为 A、B、C。当我写这个时，我希望它在终端上显示给我：
./scrypt Folder
the following:
下列：
A: file
B: file
C: file
With the code I've shown above, I get this:
使用我上面显示的代码，我得到了这个：
A: ERROR: cannot open `A' (No such file or directory)
B: ERROR: cannot open `B' (No such file or directory)
C: ERROR: cannot open `C' (No such file or directory)
that is the problem
那就是问题所在
采纳答案by Arkku
One way is to use wildcard expansion instead of ls, e.g.,
一种方法是使用通配符扩展而不是ls，例如，
for filename in ""/*; do
command "$filename"
done
This assumes that $1is the path to a directory with files in it.
这假定这$1是包含文件的目录的路径。
If you want to only operate on plain files, add a check right after doalong the lines of:
如果您只想对纯文件进行操作，请在do以下行之后添加一个检查：
[ ! -f "$filename" ] && continue
回答by Master Chief
http://mywiki.wooledge.org/ParsingLs
http://mywiki.wooledge.org/ParsingLs
Use globbing instead:
改用通配符：
for filename in ""/* ; do
<cmd> "$filename"
done
Note the quotes around $filename
注意 $filename 周围的引号
回答by sampson-chen
It's a bit unclear what you are trying to accomplish, but you can essentially do the same thing with functionality that already exists with find. For example, the following prints the contents of each file found in a folder:
有点不清楚您要完成什么，但是您基本上可以使用find. 例如，以下打印文件夹中找到的每个文件的内容：
find FolderName -type f -maxdepth 1 -exec cat {} \;
回答by ofir.elhayani
well, i think that what you meant is that the loop will show the filenames in the desired dir. so, i would do it like that:
好吧，我认为您的意思是循环将在所需目录中显示文件名。所以，我会这样做：
for filename in ""/*; do
echo "file: $filename"
done
that way the result should be (in case in the dir are 3 files and the names are A B C:
这样结果应该是（如果目录中有 3 个文件并且名称是 ABC：
`file: A
`file: B
`file: C
