Bash：按 MIME 类型查找文件的脚本
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Bash: Script for finding files by mime-type
提问by masamunedark
First, I am not experienced in scripting, so be gentle with me
首先，我在脚本方面没有经验，所以对我温柔一点
Anyway, I tried making a script for finding files by mime-type ( audio, video, text...etc), and here's the poor result I came up with.
无论如何，我尝试制作一个脚本来按 mime 类型（音频、视频、文本等）查找文件，这是我想出的糟糕结果。
#!/bin/bash
FINDPATH=""
FILETYPE=""
locate $FINDPATH* | while read FILEPROCESS
do
if file -bi "$FILEPROCESS" | grep -q "$FILETYPE"
then
echo $FILEPROCESS
fi
done
It works, but as you could guess, the performance is not so good.
它可以工作，但正如您所猜测的那样，性能并不是那么好。
So, can you guys help me make it better ? and also, I don't want to rely on files extensions.
所以，你们能帮我把它做得更好吗？而且，我不想依赖文件扩展名。
Update:
更新：
Here's what I am using now
这是我现在使用的
#!/bin/bash
FINDPATH=""
find "$FINDPATH" -type f | file -i -F "::" -f - | awk -v FILETYPE="" -F"::" ' ~ FILETYPE { print }'
采纳答案by Eric Fortis
#!/bin/bash
find | file -if- | grep | awk -F: '{print }'
回答by jm666
Forking (exec) is expensive. This runs the filecommand only once, so it is fast:
分叉 ( exec) 是昂贵的。这个file命令只运行一次，所以速度很快：
find . -print | file -if - | grep "what you want" | awk -F: '{print }'
or
或者
locate what.want | file -if -
check man file
查看 man file
-i #print mime types
-f - #read filenames from the stdin
