Bash -- 文件名中的 Rsync 变量有空格
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Bash -- Rsync variable in filename has spaces
提问by KroniK907
Been searching for hours and still cant figure this out :(
已经搜索了几个小时，但仍然无法弄清楚:(
Anyway, im creating a script that will automatically rsync about 40 different directories to 40 other directories on another server. if you want to see the entire script you can view it here: http://pastebin.com/Nt3KKvx9
无论如何，我正在创建一个脚本，该脚本将自动将大约 40 个不同的目录同步到另一台服务器上的 40 个其他目录。如果您想查看整个脚本，可以在此处查看：http: //pastebin.com/Nt3KKvx9
But the important bit is the for loop where i run rsync
但重要的一点是我运行 rsync 的 for 循环
for ((i=0; i<${#websys[@]}; i++))
do
localpath="/nusdata/staff/NUS/NUS/Systems/${kiskasys[$i]}"
remotepath="/home/www/html/nusalaska.com/html/systems/${websys[$i]}"
rsync -rlptnvz -s "$localpath" -e "ssh -p 50014" "nusak@webserver:$remotepath/"
done
The problem is that the array "kiskasys" has many directory names that have spaces in them (Example: '101 greenbrook'). I have tried making the array variables have single quotes around them, double quotes around them, escaped spaces like '\ ', and combinations of all three. I have also tried putting the $localpath in quotes, not in quotes, etc. etc.
问题是数组“kiskasys”有许多包含空格的目录名称（例如：'101 greenbrook'）。我曾尝试使数组变量在它们周围有单引号，在它们周围有双引号，像 '\ ' 这样的转义空格，以及所有三者的组合。我也试过将 $localpath 放在引号中，而不是放在引号中等等。
I guess im just confused on how the -s (--protect-args) deals with the spaces and how I can get it to work in my situation.
我想我只是对 -s (--protect-args) 如何处理空格以及如何让它在我的情况下工作感到困惑。
The error output always looks something like the following:
错误输出始终如下所示：
rsync: change_dir "/nusdata/staff/NUS/NUS/101" failed: No such file or directory (2)
or
或者
rsync: change_dir "/nusdata/staff/NUS/NUS/'101 greenbrook'" failed: No such file or directory (2)
Any help is appreciated!
任何帮助表示赞赏！
Thanks
谢谢
Found My Problem
发现我的问题
In copying my code from my script to this page I accidently copied it wrong... however in copying it wrong, what i posted above was perfectly good code that works fine haha.
在将我的代码从我的脚本复制到此页面时，我不小心复制了错误...但是在复制错误时，我上面发布的是非常好的代码，可以正常工作哈哈。
so what i posted above was the solution to my own problem.
所以我上面发布的是我自己问题的解决方案。
The original had single quotes in the localpath variable like so:
原来的 localpath 变量中有单引号，如下所示：
localpath="'/nusdata/staff/NUS/NUS/Systems/${kiskasys[$i]}'"
and the single quotes was the problem. And for everyone's benefit here is an example output
单引号是问题所在。为了大家的利益，这里是一个示例输出
echo ${kiskasys[1]}
#output would look like this:
101 greenbrook
Basically there are no special escape characters etc.
基本上没有特殊的转义字符等。
回答by larsks
For what it's worth, I'm not able to replicate your problem. If I set localpathand remotepathto a directory with spaces:
对于它的价值，我无法复制您的问题。如果我将localpath和设置remotepath为带有空格的目录：
localpath="/home/lars/tmp/so/dir1/a directory"
remotepath="/home/lars/tmp/so/dir2/a directory"
And then run your rsynccommand (modified slightly for my environment):
然后运行您的rsync命令（针对我的环境稍作修改）：
rsync -rlptvz -s "$localpath/" -e "ssh" "localhost:$remotepath/"
It Just Works. Here's the content of dir1:
它只是有效。以下是内容dir1：
dir1/a directory/file1
dir1/a directory/file3
dir1/a directory/file2
And after running rsync, dir2looks like this:
运行 rsync 后，dir2如下所示：
dir2/a directory/file1
dir2/a directory/file3
dir2/a directory/file2
Can you show a specificcommand line that results in the errors you're seeing above? Maybe run the script with the -xflag and show exactly how localpathand remotepathare set.
您能否显示导致您在上面看到的错误的特定命令行？也许运行带有-x标志的脚本并准确显示如何设置localpath和remotepath设置。
