如何在 Bash 脚本中传递带有空格的命令行参数
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How to pass command line argument with space in Bash scripts
提问by Richard
Let's say there is one script s1, and I need to pass argument $1with value foo bar, with space in it. This can be done
假设有一个 script s1，我需要传递$1带有 value 的参数foo bar，其中有空格。这是可以做到的
./s1 "foo bar"
./s1 "foo bar"
however, when I want to run the above command in another script (say s2), how should I put it? If I put it as above, foo barwill be interpreted as two arguments (to s1) rather than one.
但是，当我想在另一个脚本中运行上述命令时（比如s2），我应该怎么写？如果我把它放在上面，foo bar将被解释为两个参数（到 s1）而不是一个。
回答by cnicutar
You can try quoting $1:
您可以尝试引用$1：
./s2 ""
回答by phoxis
Use single quotes.
使用单引号。
./script 'this is a line'
./script 'this is a line'
To consider variable substitutions use double quotes
考虑变量替换使用双引号
./script "this is a line"
./script "this is a line"
回答by kch
How about:
怎么样：
./s1 foo\ bar
Would that work?
那行得通吗？
