如何在 Java 中对二维数组进行深拷贝?
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How do I do a deep copy of a 2d array in Java?
提问by
I just got bit by using .clone()
on my 2d boolean
array, thinking that this was a deep copy.
我只是.clone()
在我的 2dboolean
数组上使用了一下,认为这是一个深拷贝。
How can I perform a deep copy of my boolean[][]
array?
如何执行boolean[][]
数组的深层复制?
Should I loop through it and do a series of System.arraycopy
's?
我应该遍历它并执行一系列System.arraycopy
's 吗?
采纳答案by Rorick
Yes, you should iterate over 2D boolean array in order to deep copy it. Also look at java.util.Arrays#copyOf
methods if you are on Java 6.
是的,您应该遍历 2D 布尔数组以对其进行深度复制。java.util.Arrays#copyOf
如果您使用的是 Java 6,还要查看方法。
I would suggest the next code for Java 6:
我建议 Java 6 的下一个代码:
public static boolean[][] deepCopy(boolean[][] original) {
if (original == null) {
return null;
}
final boolean[][] result = new boolean[original.length][];
for (int i = 0; i < original.length; i++) {
result[i] = Arrays.copyOf(original[i], original[i].length);
// For Java versions prior to Java 6 use the next:
// System.arraycopy(original[i], 0, result[i], 0, original[i].length);
}
return result;
}
回答by Aaron Digulla
Yes, that's the only way to do it. Neither java.util.Arrays
not commons-lang offer deep copy for arrays.
是的,这是唯一的方法。无论是java.util.Arrays
不是公共琅提供阵列的深层复制。
回答by perimosocordiae
I'm a fan of the Arrays utility. It has a copyOf method that will do a deep copy of a 1-D array for you, so you'd want something like this:
我是 Arrays 实用程序的粉丝。它有一个 copyOf 方法,可以为你做一个一维数组的深拷贝,所以你需要这样的东西:
//say you have boolean[][] foo;
boolean[][] nv = new boolean[foo.length][foo[0].length];
for (int i = 0; i < nv.length; i++)
nv[i] = Arrays.copyOf(foo[i], foo[i].length);
回答by Karl Bennett
I've managed to come up with a recursive array deep copy. It seems to work pretty well even for multi dimensional arrays with varying dimension lengths e.g.
我设法想出了一个递归数组深拷贝。即使对于具有不同维度长度的多维数组,它似乎也能很好地工作,例如
private static final int[][][] INT_3D_ARRAY = {
{
{1}
},
{
{2, 3},
{4, 5}
},
{
{6, 7, 8},
{9, 10, 11},
{12, 13, 14}
}
};
Here is the utility method.
这是实用方法。
@SuppressWarnings("unchecked")
public static <T> T[] deepCopyOf(T[] array) {
if (0 >= array.length) return array;
return (T[]) deepCopyOf(
array,
Array.newInstance(array[0].getClass(), array.length),
0);
}
private static Object deepCopyOf(Object array, Object copiedArray, int index) {
if (index >= Array.getLength(array)) return copiedArray;
Object element = Array.get(array, index);
if (element.getClass().isArray()) {
Array.set(copiedArray, index, deepCopyOf(
element,
Array.newInstance(
element.getClass().getComponentType(),
Array.getLength(element)),
0));
} else {
Array.set(copiedArray, index, element);
}
return deepCopyOf(array, copiedArray, ++index);
}
EDIT:Updated the code to work with primitive arrays.
编辑:更新了代码以使用原始数组。
回答by SlavaSt
In Java 8 this can be accomplished as a one-liner using lambdas:
在 Java 8 中,这可以使用 lambda 作为单行代码完成:
<T> T[][] deepCopy(T[][] matrix) {
return java.util.Arrays.stream(matrix).map(el -> el.clone()).toArray($ -> matrix.clone());
}
回答by Radiodef
Here's a reflective example using java.lang.reflect.Array
which is more robust and a bit easier to follow. This method will copy any array, and deeply copies multidimensional arrays.
这是一个反射示例,使用java.lang.reflect.Array
它更健壮且更易于遵循。此方法将复制任何数组,并深度复制多维数组。
package mcve.util;
import java.lang.reflect.*;
public final class Tools {
private Tools() {}
/**
* Returns a copy of the specified array object, deeply copying
* multidimensional arrays. If the specified object is null, the
* return value is null. Note: if the array object has an element
* type which is a reference type that is not an array type, the
* elements themselves are not deep copied. This method only copies
* array objects.
*
* @param array the array object to deep copy
* @param <T> the type of the array to deep copy
* @return a copy of the specified array object, deeply copying
* multidimensional arrays, or null if the object is null
* @throws IllegalArgumentException if the specified object is not
* an array
*/
public static <T> T deepArrayCopy(T array) {
if (array == null)
return null;
Class<?> arrayType = array.getClass();
if (!arrayType.isArray())
throw new IllegalArgumentException(arrayType.toString());
int length = Array.getLength(array);
Class<?> componentType = arrayType.getComponentType();
@SuppressWarnings("unchecked")
T copy = (T) Array.newInstance(componentType, length);
if (componentType.isArray()) {
for (int i = 0; i < length; ++i)
Array.set(copy, i, deepArrayCopy(Array.get(array, i)));
} else {
System.arraycopy(array, 0, copy, 0, length);
}
return copy;
}
}