pandas 如何根据值对熊猫系列进行子集化？
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How to subset a pandas series based on value?
提问by Paco Bahena
I have a pandas series object, and i want to subset it based on a value
我有一个Pandas系列对象，我想根据一个值对它进行子集化
for example:
例如：
s = pd.Series([1,2,3,4,5,6,7,8,9,10])
how can i subset it so i can get a series object containing only elements greater or under x value. ?
我如何才能对它进行子集化，以便获得一个仅包含大于或小于 x 值的元素的系列对象。?
回答by Alexander
I believe you are referring to boolean indexingon a series.
我相信你指的是一个系列的布尔索引。
Greater than x:
大于x：
x = 5
>>> s[s > x] # Alternatively, s[s.gt(x)].
5 6
6 7
7 8
8 9
9 10
dtype: int64
Less than x(i.e. under x):
小于x（即在 x 下）：
s[s < x] # or s[s.lt(x)]
回答by DYZ
Assuming that by "greater or under x" you mean "not equal to x", you can use boolean indexing:
假设“大于或小于x”的意思是“不等于x”，则可以使用布尔索引：
s[s!=x]
