python 3中的字符串拆分格式
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String split formatting in python 3
提问by Student J
I'm trying to format this string below where one row contains five words. However, I keep getting this as the output:
我试图在下面的一行包含五个单词的地方格式化这个字符串。但是，我一直将其作为输出：
I love cookies yes I do Let s see a dog
我喜欢饼干 是的 我喜欢 让我们看一只狗
First, I am not getting 5 words in one line, but instead, everything in one line.
首先，我不是在一行中得到 5 个单词，而是在一行中得到所有内容。
Second, why does the "Let's" get split? I thought in splitting the string using "words", it will only split if there was a space in between?
其次，为什么“让我们”分裂？我想在使用“单词”分割字符串时，它只会在中间有空格的情况下分割吗？
Suggestions?
建议？
string = """I love cookies. yes I do. Let's see a dog."""
# split string
words = re.split('\W+',string)
words = [i for i in words if i != '']
counter = 0
output=''
for i in words:
if counter == 0:
output +="{0:>15s}".format(i)
# if counter == 5, new row
elif counter % 5 == 0:
output += '\n'
output += "{0:>15s}".format(i)
else:
output += "{0:>15s}".format(i)
# Increase the counter by 1
counter += 1
print(output)
采纳答案by Fredrik Pihl
As a start, don't call a variable "string" since it shadows the modulewith the same name
首先，不要调用变量“字符串”，因为它会隐藏具有相同名称的模块
Secondly, use split()to do your word-splitting
其次，split()用来做你的分词
>>> s = """I love cookies. yes I do. Let's see a dog."""
>>> s.split()
['I', 'love', 'cookies.', 'yes', 'I', 'do.', "Let's", 'see', 'a', 'dog.']
From re-module
从重新模块
\W Matches any character which is not a Unicode word character. This is the opposite of \w. If the ASCII flag is used this becomes the equivalent of [^a-zA-Z0-9_] (but the flag affects the entire regular expression, so in such cases using an explicit [^a-zA-Z0-9_] may be a better choice).
\W 匹配任何不是 Unicode 单词字符的字符。这与\w相反。如果使用 ASCII 标志，则这相当于 [^a-zA-Z0-9_]（但该标志会影响整个正则表达式，因此在这种情况下，使用显式 [^a-zA-Z0-9_] 可能是更好的选择）。
Since the 'is not listed in the above, the regexp used splits the "Let's" string into two parts:
由于'上面没有列出，所使用的正则表达式将“Let's”字符串分成两部分：
>>> words = re.split('\W+', s)
>>> words
['I', 'love', 'cookies', 'yes', 'I', 'do', 'Let', 's', 'see', 'a', 'dog', '']
This is the output I get using the strip()-approach above:
这是我使用上面的 strip() 方法得到的输出：
$ ./sp3.py
I love cookies. yes I
do. Let's see a dog.
The code could probably be simplified to this since counter==0and the else-clause does the same thing. I through in an enumeratethere as well to get rid of the counter:
代码可能会简化为这个，因为counter==0else 子句做同样的事情。我也在那里进行了枚举以摆脱计数器：
#!/usr/bin/env python3
s = """I love cookies. yes I do. Let's see a dog."""
words = s.split()
output = ''
for n, i in enumerate(words):
if n % 5 == 0:
output += '\n'
output += "{0:>15s}".format(i)
print(output)
回答by Stephan
words = string.split()
while (len(words))
for word in words[:5]
print(word, end=" ")
print()
words = words[5:]
That's the basic concept, split it using the split() method
这是基本概念，使用 split() 方法拆分它
Then slice it using slice notation to get the first 5 words
然后使用切片符号对其进行切片以获得前 5 个单词
Then slice off the first 5 words, and loop again
然后切掉前5个单词，再次循环
