bash 如何遍历所有打印键和值的 ENV 变量？
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How to iterate through all the ENV variables printing key and value?
提问by Gajus
I'd like to iterate through the variables in envprinting:
我想遍历env打印中的变量：
name: ${name} value: ${value}
Simply splitting by line break and iterating does not work, because of multi-line values, e.g.
由于多行值，例如，简单地按换行符和迭代拆分是行不通的
SERVER_TLS_SERVER_CRT=-----BEGIN CERTIFICATE-----
foo
-----END CERTIFICATE-----
The use case is to workaround Docker limitationthat restricts passing multi-line variables via --env-file.
用例是解决Docker 限制，该限制限制通过--env-file.
采纳答案by geirha
Here's the solution from #bash.
这是#bash 的解决方案。
unset IFS
args=() i=0
for var in $(compgen -e); do
printf -v 'args[i++]' -e%s=%s "$var" "${!var}"
done
I initially thought the idea was to output, hence printf %q was necessary, but that's not the case when just building an arguments array, so it can be simplified to this:
我最初认为这个想法是输出，因此 printf %q 是必要的，但在构建参数数组时并非如此，因此可以简化为：
unset IFS
args=()
for var in $(compgen -e); do
args+=( "-e$var=${!var}" )
done
回答by anubhava
You can use env -0to get a null terminated list of name=valuepairs and use a for loop to iterate:
您可以使用env -0以获取空终止的name=value对列表并使用 for 循环进行迭代：
while IFS='=' read -r -d '' n v; do
printf "'%s'='%s'\n" "$n" "$v"
done < <(env -0)
Above script use process substitution, which is a BASH feature. On older shells you can use a pipeline:
上面的脚本使用了进程替换，这是一个 BASH 特性。在较旧的 shell 上，您可以使用管道：
env -0 | while IFS='=' read -r -d '' n v; do
printf "'%s'='%s'\n" "$n" "$v"
done
