^word^replacement^ 在 Bash 中的所有匹配项？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/649070/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
^word^replacement^ on all matches in Bash?
提问by pisswillis
To clarify, I am looking for a way to perform a globalsearch and replace on the previous command used. ^word^replacement^only seems to replace the first match.
为了澄清，我正在寻找一种方法来执行全局搜索并替换先前使用的命令。^word^replacement^似乎只替换了第一场比赛。
Is there some setoption that is eluding me?
有什么set选择让我望而却步吗？
回答by John Feminella
Try this:
尝试这个：
$ echo oneone
oneone
$ !!:gs/one/two/ # Repeats last command; substitutes 'one' --> 'two'.
twotwo
回答by Paused until further notice.
Blending my answer herewith John Feminella's you can do this if you want an alias:
融合了我的答案在这里与约翰Feminella的，如果你想要一个别名，你可以这样做：
$alias dothis='`history -p "!?monkey?:gs/jpg/png/"`'
$ls *.jpg
monkey.jpg
$dothis
monkey.png
The !! only does the previous command, while !?string? matches the most recent command containing "string".
这 ！！只执行上一个命令，而 !?string? 匹配包含“string”的最新命令。
回答by l3x
This solution uses Bash Substring Replacement:
此解决方案使用 Bash 子字符串替换：
$ SENTENCE="1 word, 2 words";echo "${SENTENCE//word/replacement}"
1 replacement, 2 replacements
Note the use of the double slashes denotes "global" string replacement.
请注意，双斜线的使用表示“全局”字符串替换。
This solution can be executed in one line.
此解决方案可以在一行中执行。
Here's how to globally replace a string in a file named "myfile.txt":
以下是如何全局替换名为“myfile.txt”的文件中的字符串：
$ sed -i -e "s/word/replacement/g" myfile.txt
回答by pisswillis
A nasty way to get around this could be something like this:
解决这个问题的一种讨厌的方法可能是这样的：
Want to echo BAABAArather than BLABLAby swapping L's for A's
想要回声BAABAA而不是BLABLA将 L 换成 A
$ echo "BLABLA"
BLABLA
$ `echo "!!" | sed 's/L/A/g'`
$(echo "echo "BLABLA" " | sed 's/L/A/g')
BAABAA
$
Unfortunately this technique doesn't seem to work in functions or aliases.
不幸的是，这种技术似乎不适用于函数或别名。
回答by zhumaomao
I test it on SUSE 10.1. "^word^replacement^" doesn't work, while "^word^replacement" works well. for a instance:
我在 SUSE 10.1 上对其进行了测试。"^word^replacement^" 不起作用，而 "^word^replacement" 工作得很好。例如：
linux-geek:/home/Myworks # ls /etc/ld.so.conf
/etc/ld.so.conf
linux-geek:/home/Myworks # ^ls^cat
cat /etc/ld.so.conf
/usr/X11R6/lib/Xaw3d
/usr/X11R6/lib
/usr/i486-linux-libc5/lib=libc5
/usr/i386-suse-linux/lib
/usr/local/lib
/opt/kde3/lib
/opt/gnome/lib
include /etc/ld.so.conf.d/*.conf
linux-geek:/home/Myworks #
