PHP：日期函数获取当前日期的月份
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PHP: date function to get month of the current date
提问by iamjonesy
I want to be able to figure out the month of the current date variable. I'm ex vb.net and the way to do it there is just date.Month. How do I do this in PHP?
我希望能够找出当前日期变量的月份。我是 vb.net 的前任，这样做的方法只有date.Month. 我如何在 PHP 中做到这一点？
Thanks,
谢谢，
Jonesy
琼斯
I used date_format($date, "m"); //01, 02..12
我用了 date_format($date, "m"); //01, 02..12
This is what I wanted, question now is how do I compare this to an int since $monthnumber = 01just becomes 1
这就是我想要的，现在的问题是我如何将它与 int 进行比较，因为它$monthnumber = 01刚刚变成1
回答by fabrik
date('m')or date('n')or date('F')...
date('m')或date('n')或date('F')...
Update
更新
mNumeric representation of a month, with leading zeros 01 through 12
nNumeric representation of a month, without leading zeros 1 through 12
FAlphabetic representation of a month January through December
m月份的数字表示，前导零为 01 到 12
n月份的数字表示，没有前导零 1 到 12
F一月到十二月的字母表示
....see the docs link for even more options.
....查看文档链接以获取更多选项。
回答by oezi
What does your "data variable" look like? If it's like this:
你的“数据变量”是什么样的？如果是这样：
$mydate = "2010-05-12 13:57:01";
You can simply do:
你可以简单地做：
$month = date("m",strtotime($mydate));
For more information, take a look at dateand strtotime.
EDIT:
编辑：
To compare with an int, just do a date_format($date,"n");which will give you the month without leading zero.
要与 int 进行比较，只需执行 a 即可date_format($date,"n");为您提供没有前导零的月份。
Alternatively, try one of these:
或者，尝试以下方法之一：
if((int)$month == 1)...
if(abs($month) == 1)...
Or something weird using ltrim, round, floor... but date_format() with "n" would be the best.
或者使用 ltrim、round、floor 进行一些奇怪的操作……但是带有“n”的 date_format() 会是最好的。
回答by Pramendra Gupta
$unixtime = strtotime($test);
echo date('m', $unixtime); //month
echo date('d', $unixtime);
echo date('y', $unixtime );
回答by Hannes
as date_format uses the same format as date ( http://www.php.net/manual/en/function.date.php) the "Numeric representation of a month, without leading zeros" is a lowercase n .. so
由于 date_format 使用与日期相同的格式（http://www.php.net/manual/en/function.date.php）“月份的数字表示，没有前导零”是小写 n .. 所以
echo date('n'); // "9"
回答by J-a-n-u-s
As it's not specified if you mean the system's current date or the date held in a variable, I'll answer for latter with an example.
由于它没有指定是系统的当前日期还是变量中保存的日期，我将用一个例子来回答后者。
<?php
$dateAsString = "Wed, 11 Apr 2018 19:00:00 -0500";
// This converts it to a unix timestamp so that the date() function can work with it.
$dateAsUnixTimestamp = strtotime($dateAsString);
// Output it month is various formats according to http://php.net/date
echo date('M',$dateAsUnixTimestamp);
// Will output Apr
echo date('n',$dateAsUnixTimestamp);
// Will output 4
echo date('m',$dateAsUnixTimestamp);
// Will output 04
?>
回答by e102
To compare with an int do this:
要与 int 进行比较，请执行以下操作：
<?php
$date = date("m");
$dateToCompareTo = 05;
if (strval($date) == strval($dateToCompareTo)) {
echo "They are the same";
}
?>
