带有索引的打印矩阵python
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print matrix with indicies python
提问by user1692261
I have a matrix in Python defined like this:
我在 Python 中有一个矩阵定义如下：
matrix = [['A']*4 for i in range(4)]
How do I print it in the following format:
我如何以以下格式打印它：
0 1 2 3
0 A A A A
1 A A A A
2 A A A A
3 A A A A
采纳答案by Sukrit Kalra
This function matches your exact output.
此功能与您的确切输出相匹配。
>>> def printMatrix(testMatrix):
print ' ',
for i in range(len(testMatrix[1])): # Make it work with non square matrices.
print i,
print
for i, element in enumerate(testMatrix):
print i, ' '.join(element)
>>> matrix = [['A']*4 for i in range(4)]
>>> printMatrix(matrix)
0 1 2 3
0 A A A A
1 A A A A
2 A A A A
3 A A A A
>>> matrix = [['A']*6 for i in range(4)]
>>> printMatrix(matrix)
0 1 2 3 4 5
0 A A A A A A
1 A A A A A A
2 A A A A A A
3 A A A A A A
To check for single length elements and put an &in place of elements with length > 1, you could put a check in the list comprehension, the code would change as follows.
要检查单个长度的元素并&替换长度 > 1 的元素，您可以在列表理解中进行检查，代码将更改如下。
>>> def printMatrix2(testMatrix):
print ' ',
for i in range(len(testmatrix[1])):
print i,
print
for i, element in enumerate(testMatrix):
print i, ' '.join([elem if len(elem) == 1 else '&' for elem in element])
>>> matrix = [['A']*6 for i in range(4)]
>>> matrix[1][1] = 'AB'
>>> printMatrix(matrix)
0 1 2 3 4 5
0 A A A A A A
1 A AB A A A A
2 A A A A A A
3 A A A A A A
>>> printMatrix2(matrix)
0 1 2 3 4 5
0 A A A A A A
1 A & A A A A
2 A A A A A A
3 A A A A A A
回答by icecrime
>>> for i, row in enumerate(matrix):
... print i, ' '.join(row)
...
0 A A A A
1 A A A A
2 A A A A
3 A A A A
I guess you'll find out how to print out the first line :)
我想你会知道如何打印第一行:)
回答by Ashwini Chaudhary
Something like this:
像这样的东西：
>>> matrix = [['A'] * 4 for i in range(4)]
>>> def solve(mat):
print " ", " ".join([str(x) for x in xrange(len(mat))])
for i, x in enumerate(mat):
print i, " ".join(x) # or " ".join([str(y) for y in x]) if elements are not string
...
>>> solve(matrix)
0 1 2 3
0 A A A A
1 A A A A
2 A A A A
3 A A A A
>>> matrix = [['A'] * 5 for i in range(5)]
>>> solve(matrix)
0 1 2 3 4
0 A A A A A
1 A A A A A
2 A A A A A
3 A A A A A
4 A A A A A
回答by Muhammed Rafi CH
a=[["A" for i in range(4)] for j in range(4)]
for i in range(len(a)):
print()
for j in a[i]:
print("%c "%j,end='')
it will print like this:
它会像这样打印：
A A A A
A A A A
A A A A
A A A A
