bash 如何用bash中的另一个字符替换字符串的最后一个字符？
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How can I replace the last character of a string with another character in bash?
提问by user2709885
I am working on a small code in bash, but I am stuck on a small problem.
I have a string, and I want to replace the last letter of that string with s.
我正在用 bash 编写一个小代码，但我遇到了一个小问题。我有一个字符串，我想将该字符串的最后一个字母替换为s.
For example: I am taking all the files that end in cand replacing the last cwith s.
例如：我把所有的文件结束c和更换，最后c用s。
for file in *.c; do
# replace c with s
echo $file
Can someone please help me?
有人可以帮帮我吗？
回答by Henk Langeveld
for file in *.c; do
echo "${file%?}s"
done
In parameter substitution, ${VAR%PAT} will remove the last characters matching PAT from variable VAR.
Shell patterns *and ?can be used as wildcards.
在参数替换中，${VAR%PAT} 将从变量 VAR 中删除与 PAT 匹配的最后一个字符。Shell 模式*和?可以用作通配符。
The above drops the final character, and appends "s".
以上删除了最后一个字符，并附加了“s”。
回答by iruvar
Use parameter substitution. The following accomplishes suffix replacement. It replaces one instance of canchored to the right with s.
使用参数替换。下面完成后缀替换。它将c锚定到右侧的一个实例替换为s。
for file in *.c; do
echo "${file/%c/s}"
done
回答by jkshah
Use renameutility if you would want to get away with loop
rename如果您想摆脱循环，请使用实用程序
rename -f 's/\.c$/.s/' *.c
